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Zanzabum
2 years ago
9

Sari is factoring the polynomial 2x2+5x+3. If one factor is (x+1), wh

Mathematics
2 answers:
Irina-Kira [14]2 years ago
4 0

Answer:

2x+3

Step-by-step explanation:

if we need to find any polynomial factor you need to do

2x^2 +5x +3 is divided by the known factor x+1

if you have cas calculator

go to menu- algebra- factor -type the 2x^2 +5x +3

the answer will be 2x+3

victus00 [196]2 years ago
3 0

Answer:

the second factor is 2x+3

Second option is correct.

Step-by-step explanation:

The given polynomial is 2x^2+5x+3

One factor of polynomial is x+1

It means that this factor completely divide the polynomial and the quotient would be the second factor.

Therefore, second factor is given by

\frac{2x^2+5x+3}{x+1}

Numerator can be factored as

2x^2+5x+3\\\\=2x^2+3x+2x+3\\\\=x(2x+3)+1(2x+3)\\\\\=(2x+3)(x+1)

Hence, the second factor is

\frac{(2x+3)(x+1)}{x+1}

Cancel the common factor from numerator and denominator

the second factor is 2x+3

Second option is correct.

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iris [78.8K]

Answer:

The answer to your question is          x ≠ -10   x ≠ 2     x ≠ -2

Solution                                                \frac{(x- 8)(x + 2)}{(x + 8)(x - 2)}      

Step-by-step explanation:

Process

1.- Factor all the polynomials

              \frac{x^{2} -3x - 40}{x^{2} + 8x - 20} / \frac{x^{2}+ 13x + 40}{x^{2}+ 12x + 20} = \frac{(x-8)(x + 5)}{(x + 10)(x- 2)} / \frac{(x+ 8)(x + 5)}{(x + 10)(x + 2)}

2.- Invert the second term

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3.- Simplify

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Answer:

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Answer:

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Step-by-step explanation:

1.2 x 2 = 2.4

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2 years ago
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