Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
The local gym holds three 45-minute workout sessions and two 30-minute sessions each week. Then the, total number of minutes Judy worked out for the week was 155 minutes.
We are to determine the total number of minutes Judy worked out for the week.
The gym holds three 45-minute workout sessions and two 30-minute sessions each week
So,
We can write,
The total number of minutes the gym holds workout sessions is
3 × 45 + 2 × 30
= 135 + 60
= 195 minutes
Also, from the information,
Judy left 5 minutes early during the 30-minute sessions and 10 minutes early during the 45-minute sessions.
The total number of minutes Judy didn't attend is
= 3 × 10 + 2 × 5
= 30 + 10
= 40 minutes
Then,
The total number of minutes Judy worked out for the week was,
= 195 minutes - 40 minutes
= 155 minutes
Therefore,
The total number of minutes Judy worked out for the week was 155 minutes.
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Answer:
D. just sub x = 1, and if the y you get is 5 then that's the answer
Answer:
332
the reason why I think it's $332 is because if you do 1,994 / 6 then that equals 332 I don't know if you get it right if you do great job if you don't I understand
