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Anna [14]
4 years ago
9

How many solutions does this problem have? 3(y+41)=3y+123

Mathematics
1 answer:
Natali [406]4 years ago
8 0

Answer:

The answer is many solutions

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(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{4}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{2}}}\implies \cfrac{3}{2}

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The graph shows the distance y, in inches, a pendulum moves to the right (positive displacement) and to the left (negative displ
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<h2>1 second.</h2>

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