Answer:
x ≥ -7/2
Step-by-step explanation:
3 + 2x ≥ -4
Subtract 3 from each side
3-3 + 2x ≥ -4-3
2x ≥ -7
Divide each side by 2
2x/2 ≥ -7/2
x ≥ -7/2
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5: Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
Answer:
2, 4, 6, 8 , 10
Step-by-step explanation:
L=length W=width
perimeter=2Lx2W
196=2L+2W
Length can be written as 6W because it is 6 times the width. We then substitute this in so all the terms are the same
196=2(6W)+2W
196=12W+2W
196=14W
W=14cm
L= (14x6) 84cm
Angie buys 1 software package and 3 months of game play
Kenny buys 1 software package and 4 months of game play
price of each software package = $20
total cost = $117
cost of one month game play = ?
let y is the cost of one month play
Angie buys 3 months game play and paid $20 = 20 + 3y
Kenny buys 4 months game play and paid $20 = 20 + 4y
total cost of both is $117
So the equation becomes,
(20 + 3y) + (20 + 4y) = 117
7y + 40 = 117
7y = 117 - 40
7y = 77
dividing with 7 on both sides, we get
y = 11
so, $11 is the cost of one month game play
