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LenKa [72]
3 years ago
10

A manufacturer knows that their items have a normally distributed lifespan, with a mean of 15 years, and standard deviation of 3

.7 years. If you randomly purchase 22 items, what is the probability that their mean life will be longer than 13 years?
Mathematics
1 answer:
Gala2k [10]3 years ago
7 0

Answer:

The probability that their mean life will be longer than 13 years = .9943 or 99.43%

Step-by-step explanation:

Given -

Mean (\nu  ) = 15 years

Standard deviation (\sigma  ) = 3.7 years

Sample size ( n ) =22

Let \overline{X} be the mean life of manufacturing items

the probability that their mean life will be longer than 13 years =

P(\overline{X}>  13) =  P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}>  \frac{13 - 15 }{\frac{3.7}{\sqrt{22}}})       (Z =\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}})

                    =  P(Z> -2.53)

                    = 1 - P(Z <  -2.53)       Using Z table

                    = 1 - .0057

                    =  .9943

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Answer:

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Step-by-step explanation:

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True for all X

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What is the slope of the line that passes through (8,5), (-7,20)?
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2 years ago
Use the algebraic procedure explained in section 8.9 in your book to find the derivative of f(x)=1/x. Use h for the small number
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Answer:

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Answer:

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3 0
3 years ago
4x-y=10 as coordinates with the y as -6
IgorC [24]

Answer:

(1,-6)

Step-by-step explanation:

4x - y = 10

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Check your answer:

4x - y = 10

4(1) - (-6) = 10

4 + 6 = 10

10 = 10

This statement is correct

Hope this helps!

6 0
2 years ago
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