Answer: 94 child tickets
<u>Step-by-step explanation:</u>
Let x represent child tickets
Let y represent adult tickets
Cost Equation: 5.70x + 9.75y = 1306.10
Quantity Equation: x + y = 173
Solve the system of equations using the elimination method:
Multiply the Quantity Equation by -5.70
5.70x + 9.75y = 1306.10
<u> -5.70x - 5.70y</u> = <u>-986.10</u>
4.05y = 320.00
<u> ÷4.05 </u> <u>÷4.05 </u>
y = 79
x + y = 173
x + 79 = 173
x = 94
Answer:
16/33
Step-by-step explanation:
12C4(total possible outcomes)=495
Since there are 6 married couples there must be 6*[2C2×10C2]=270
must subtracted 15 since when there are 2 couples in a group would have doubled 270-15=255
the no of groupings with no married couples 495-255 =240
probability=no of favourable outcomes /no of possible outcome
probability=240/495= 16/33
Answer:
-3/5
Step-by-step explanation:
1. figure c
2.figure b
3. figure a b and c