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3 years ago

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Mathematics

2 answers:

a_sh-v [17]3 years ago

8 0

Answer:

1)16cm^2

4)675cm^2

Step-by-step explanation: I think you might've got some of the other one's wrong

goldfiish [28.3K]3 years ago

5 0

Answer:

1.16

2. 21

3. 252

4. 675

just directly substitute the givens to the formula.

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Colossus Added to six flags st. Louis in 1986, the Colossus is a giant Ferris wheel. Its diameter is 165 feet, it rotates at a r

NemiM [27]

Given:

D=165 feet and the frequency of the motion is 1.6 revolutions per minute.

Solution:

The radius is half of the diameter.

The radius of the wheel is 82.5 feet.

$T=\frac{1}{1.6} \text{ minutes}$

As we know: $\omega=\frac{2\pi}{T}$

Substitute the value of T in the above formula.

$\omega=\frac{2\pi}{\frac{1}{1.6}}\\\omega=3.2\pi$

If the center of the wheel is at the origin then for $t=0$ the rest position is $-a$ .

This can be written as:

$h(t)=-a\cos(\omega t)\\h(t)=-82.5cos(32.\pi t)$

The actual height of the rider from the ground is:

$h(t)=\text{ Initial height from bottom}+\text{ radius}-82.5\cos(3.2\pi t)\\h(t)=15+82.5-82.5\cos(3.2\pi t)\\h(t)=97.5-82.5\cos(3.2\pi t)$

The required equation is $h(t)=97.5-82.5\cos(3.2\pi t)$ .

3 0

3 years ago

Please help with 15, 17 and 19

Irina-Kira [14]

Given:

15. $\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)$

17. $\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)$

19. $2^{\log_2100}$

To find:

The values of the given logarithms by using the properties of logarithms.

Solution:

15. We have,

$\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)$

Using property of logarithms, we get

$\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)=1$ $[\because \log_aa=1]$

Therefore, the value of $\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)$ is 1.

17. We have,

$\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)$

Using properties of logarithms, we get

$\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-\log_{\frac{3}{4}}\left(\dfrac{3}{4}\right)$ $[\because \log_a\dfrac{m}{n}=-\log_a\dfrac{n}{m}]$

$\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-1$ $[\because \log_aa=1]$

Therefore, the value of $\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)$ is -1.

19. We have,

$2^{\log_2100}$

Using property of logarithms, we get

$2^{\log_2100}=100$ $[\because a^{\log_ax}=x]$

Therefore, the value of $2^{\log_2100}$ is 100.

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3 years ago

Be Precise What is the difference between a terminating decimal and a repeating <br> decimal?

matrenka [14]

Answer:

Terminating decimals have a finite number of digits after the decimal point. Repeating decimals have one or more repeating numbers or sequences of numbers after the decimal point, which continue infinitely.

5 0

3 years ago

Solve 5ax + 6 ax = 7ax+ 8 for x. Assume a # 0. O A. x = = B. x = 2a ( C. 2 = D. x = a n

lesya [120]

5ax+6ax=7ax+8

5ax+6ax-7ax=8

4ax=8

x= 8/4a

x=2a

7 0

2 years ago

Which answer choice is a solution to the inequality 1.5x + 3.75 greater than or equal to 5.5

irga5000 [103]

Answer:

x≥ $\frac{7}{6}$

Step-by-step explanation:

given 1.5x+3.75≥5.5

→ 1.5x≥5.5-3.75

→ 1.5x≥1.75

→ x≥ $\frac{1.75}{1.5}$

→ x≥ $\frac{7}{6}$

8 0

3 years ago

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