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Arturiano [62]
2 years ago
13

Next part of it.....​

Mathematics
2 answers:
a_sh-v [17]2 years ago
8 0

Answer:

1)16cm^2

2)

3)

4)675cm^2

Step-by-step explanation: I think you might've got some of the other one's wrong

goldfiish [28.3K]2 years ago
5 0

Answer:

1.16

2. 21

3. 252

4. 675

just directly substitute the givens to the formula.

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In the diagram, AC =BD.<br><br> A.true<br> B.false
nikdorinn [45]

Answer:

B.False

Step-by-step explanation:

Because it built different

4 0
3 years ago
The diameter of a cylindrical construction pipe is 6 ft. If the pipe is 26 ft long, what is its volume?
Mandarinka [93]

Answer:

Step-by-step explanation:

First find the area of the circular base. The diameter is 6, so the radius is 3.

A circle is pi r square, so it is 3.14 x 3^2, = 28.26

Multiply that by the length 28.26 x 26 = 734.76, which rounds to 735 cubic feet.

5 0
3 years ago
255,250,245,... Find the 40th term.
Brut [27]
An=-5n+260
A40=60
So the Awnser is 60


(Hope this helped!!)
5 0
2 years ago
Will give brainliest
Tamiku [17]

Answer:

D. promoting general friendliness

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
How many different integers between $100$ and $500$ are multiples of either $6,$ $8,$ or both?
nirvana33 [79]
We need to find the number of integers between 100 and 500 that can be divided by 6, 8, or both. Now, to do this, we must as to how many are divisible by 6 and how many are multiples of 8.

The closest number to 100 that is divisible by 6 is 102. 498 is the multiple of 6 closest to 500. To find the number of multiple of 6 from 102 to 498, we have

n = \frac{498-102}{6} + 1
n = 67

We can use the same approach, to find the number of integers that are divisible by 8 between 100 and 500. 

n = \frac{496-104}{8} + 1
n = 50

That means there are 67 integers that are divisible by 6 and 50 integers divisible by 8. Remember that 6 and 8 share a common multiple of 24. That means the numbers 24,  48, 72, 96, etc are included in both lists. As shown below, there are 16 numbers that are multiples of 24.

n = \frac{480-120}{24} + 1
n = 16

Since we counted them twice, we subtract the number of integers that are divisible by 24 and have a final total of 67 + 50 - 16 = 101. Hence there are 101 integers that are divisible by 6, 8, or both.

Answer: 101


8 0
3 years ago
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