Looks like the expression is
(2⁸ • 5⁻⁵ • 19⁰) • (5⁻² / 2³)⁴ • 2²⁸
First, any positive number raised to 0 is 1:
(2⁸ • 5⁻⁵ • 1) • (5⁻² / 2³)⁴ • 2²⁸
(2⁸ • 5⁻⁵) • (5⁻² / 2³)⁴ • 2²⁸
Exponents in a denominator can be rewritten as negative exponents in the numerator:
(2⁸ • 5⁻⁵) • (5⁻² • 2⁻³)⁴ • 2²⁸
Distribute the 4th power across the product 5⁻² • 2⁻³ :
(5⁻² • 2⁻³)⁴ = 5⁻⁸ • 2⁻¹²
so we have
(2⁸ • 5⁻⁵) • (5⁻⁸ • 2⁻¹²) • 2²⁸
Multiplication is associative, so we can ignore the parentheses. Combine factors with equal bases and simplify the exponents:
2⁸ • 5⁻⁵ • 5⁻⁸ • 2⁻¹² • 2²⁸
2⁸⁻¹²⁺²⁸ • 5⁻⁵⁻⁸
2²⁴ • 5⁻¹³
Rewrite the negative exponent as a positive one:
2²⁴ / 5¹³
-5(x+8)-3x
simplified would be
-8x-40
Answer:
<u><em>Relative frequencies</em></u>
Growth mind set fixed mind set Total
Attendance
every practice 0.7 0.3 1
missed at-least
one practice 0.1344 0.8656 1
<u>Step-by-step explanation:</u>
Growth mind set fixed mind set total
Attendance
every practice 28 12 40
missed at-least
one practice 9 58 67
<u><em>Relative frequencies</em></u>
Growth mind set fixed mind set Total
Attendance
every practice 
1
missed at-least
one practice 
1
<u><em>Final answer</em></u>:-
<u><em>Relative frequencies</em></u>
Growth mind set fixed mind set Total
Attendance
every practice 0.7 0.3 1
missed at-least
one practice 0.1344 0.8656 1
Answer:
see below
Step-by-step explanation:
It is given that the roll of fencing is 36 ft long. Hence the perimeter of the fencing is 36 ft long.
Since the fence is to be rectangular,
Perimeter = (2 x Length ) + (2 x Width) = 36 feet
The quickest would be using calculus, but the most simple way (without using polynomials) would be to simply list the possibilities for Length and Width:
If we consider only half of the perimeter, i.e only 1 Length and 1 Width:
From the formula above,
(1/2) of Perimeter = Length + Width = 18 feet
Given that the Length & Width are to be whole numbers AND that the sum of Length & Width adds up to 18, then the possible dimensions and area are as follows:
Assemble a table in the following format:
Length x Width = Area
18 x 1 = 18
17 x 2 = 34
16 x 3 = 48
15 x 4 = 60
14 x 5 = 70
13 x 6 = 78
12 x 7 = 84
11 x 8 = 88
10 x 9 = 90
9 x 10 = 90 (anything from here onward basically repeats the previous lines, so we ignore this line and any others that follow)
a) The possible dimensions are everything listed in the table above except the last line which is repeated
b) we can see plainly that the maximum area is 10ft x 9ft = 90 sq feetand the minimum area is 18ft x 1ft = 18 sq feet
