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2 years ago

a board that is 12 feet long is to be cut into five pieces of equal length. how long will each piece of wood be?

Mathematics

2 answers:

lisov135 [29]2 years ago

4 0

Answer:

2.4

Step-by-step explanation:

You would divide the 12 by 5 because you need 5 pieces that are equal

Arte-miy333 [17]2 years ago

3 0

Answer:

2.4 feet long

Step-by-step explanation:

12/5, 12 feet long divided by 5 feet

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Let f(t) give the number of liters of fuel oil burned in t days, and w(r) the liters burned in r weeks. Find a formula for w by

viktelen [127]

Answer:

7 f(t)

Step-by-step explanation:

So, our f(t) is the number of liters burned in t days. If t is 1, f(t)=f(1) and so on for every t.

w(r) id the number of liters in r weeks. This is, in one week there are w(1) liters burned.

As in one week there are 7 days, we can replace the r, that is a week, by something that represents 7 days. As 1 day is represented by t, one week can be 7t (in other words r = 7t). So, we have that the liters burned in one week are:

w(r) = w[7f(t)]

So, we represented the liters in one week by it measure of days.

So, we can post that the number of liters burned in 7 days is the same as the number of liters burned 1 day multiplied by 7 times. So:

w (r) = w[7 f(t)] = 7 f(t)

Here we hace the w function represented in terms of t instead of r.

3 0

3 years ago

On Thursday, 72% of the customers at a frozen yogurt shop ordered vanilla frozen yogurt. If 180 customers ordered vanilla frozen

Ber [7]

180 of 72% is 129.6. 180*72= 12960. Since 72% = .72, you need to put the decimal 2 places behind the decimal.

6 0

3 years ago

Read 2 more answers

Consider the two data sets below:

alina1380 [7]

Answer:

Option c) The data sets will have the same values of their interquartile range.

Explanation:

1. The values are in order: they are in increasing oder, from lowest to highest value.

2. Calculate the interquartile range.

Interquartile range, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

Data Set 1: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

Data Set 2: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: First quartile

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

Third quartile

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: First quartile

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

Third quartile

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

An outlier will change the range because the range is the maximum value less the minimum value.

5 0

3 years ago

A car used 5 2/3 gallons of fuel on a 3 hour trip. How many gallons were used each hour?

mr_godi [17]

Answer:

2. 1 8/9 gallons

Step-by-step explanation:

5 2/3 divided by 3

5.66666667/3 = 1.88888889

.88888889 = 8/9

1 + 8/9 = 1 8/9

5 0

3 years ago

The cost C (in dollars) of making n watches is represented by C=15n 85. How many watches are made when the cost is $385?

FromTheMoon [43]

We know that C is 385, so we can plug that in to get the equation 385=15n+85. To find the number of watches, we have to solve for n.
To do that we have to...

385=15n+85

First subtract both sides of the equal sign by 85 (because we need to do the opposite)

300=15n (because 85-85 is zero, so we eliminated that, and 385-85 is 300)

Now we divide both sides of the equal sign by 15 (again, opposites)

20=n (because 15n/15 leaves us with n since both 15s cancel out, and 300/15 is 20)

So the number of watches made were 20.

7 0

3 years ago