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inessss [21]
3 years ago
15

Solve cosx+sqrt3sinx=2

Mathematics
1 answer:
Nutka1998 [239]3 years ago
4 0
Use substitution: sinx = sqrt(1-cos^2)

2- cos x = \sqrt{3} \sqrt{1-cos^2 x} \\  \\ (2-cos x)^2 = 3(1-cos^2 x)

At this point, use another substitution, u = cos x
Then solve the quadratic for u

(2-u)^2 = 3(1-u^2) \\  \\ 4u^2 -4u+1 = 0 \\  \\ u = \frac{1}{2}

Sub back in cos x

cos x = \frac{1}{2}  \\  \\ x = \frac{\pi}{3}
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