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Anestetic [448]
3 years ago
9

☆☆PLEASE HELP ASAP!!☆☆

Mathematics
1 answer:
liraira [26]3 years ago
4 0

Answer:

The new expression is p' = 5\cdot x^{2}+11\cdot x^{4}-9\cdot x^{15}+14\cdot x^{19}+12\cdot x^{22}.

Step-by-step explanation:

A polynomial is a sum of algebraic monomials such that:

p = \Sigma_{i=0}^{n} c_{i}\cdot x^{i}

Where n is the degree of the polynomial and c_{i} is the i-th coefficient of the polynomial. A 22nd degree polynomial has n = 22, so that given polynomial must added by a monomial with grade 22. Thus:

If p = 5\cdot x^{2} + 11\cdot x^{4}-9\cdot x^{15}+14\cdot x^{19} and q = 12\cdot x^{22}, then we have:

p' = p+q

p' = 5\cdot x^{2}+11\cdot x^{4}-9\cdot x^{15}+14\cdot x^{19}+12\cdot x^{22}

The new expression is p' = 5\cdot x^{2}+11\cdot x^{4}-9\cdot x^{15}+14\cdot x^{19}+12\cdot x^{22}.

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