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3 years ago

36 in the ratio of 2:3:4

1 answer:

5 0

The ratio of three numbers are 2:3:4.

Let the rational between the three numbers be x, hence the three numbers be 2x, 3x,and 4x.

If their average is 36, what are the numbers

We know the average = sum of the numbers / no. Of numbers.

(2x+3x+4x) /3=36

9x/ 3= 36

3x =36

X= 36/ 3

X= 12

The rational is 12

Answer the three number are 24, 36, and 48.

HOPE THIS HELP!!

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Answer:

sinx =1-\frac{1}{2} (x-\frac{\pi}{2} )^2+\frac{1}{24} (x-\frac{\pi}{2} )^4-\frac{1}{720} (x-\frac{\pi}{2} )^6+\frac{1}{40320} (x-\frac{\pi}{2} )^8+...

Step-by-step explanation:

given that f(x) = sin x

we have to find the Taylor series for that

$f(x) = sin x : f( = 1\\f'(x) = cos x :(f'\frac{\pi}{2})=0\\f"(x) = -sinx :f" (\frac{\pi}{2}) =-1\\f^4 (x) = -cosx : f^4 (\frac{\pi}{2}) =0$

and so on.

i.e. 2nd, 4th, 6th terms would be 0

and also 1st, 5th, 9th terms would be positive for f value and 3rd, 9th,... would be negative

Using the above we can write Taylor series as

$f(x) = f(a)+\frac{f'(a)}{1!} (x-\frac{\pi}{2}) +...+f^n(a) /n! (x- \frac{\pi}{2})^n+...$

$sinx =1-\frac{1}{2} (x-\frac{\pi}{2} )^2+\frac{1}{24} (x-\frac{\pi}{2} )^4-\frac{1}{720} (x-\frac{\pi}{2} )^6+\frac{1}{40320} (x-\frac{\pi}{2} )^8+...$

This is valid for all real values of x.

x ∈ $(-\infty, infty)$

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3 years ago