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3 years ago

WHAT IS 3.962 ROUNDED TO THE NEAREST HUNDRETH AND ONES PLACE HALLPPP LOL

Mathematics

2 answers:

EleoNora [17]3 years ago

6 0

Nearest hundredth: 3.96
Nearest ones: 4

MArishka [77]3 years ago

6 0

The nearest hundreth place is 3.96
The nearest ones place is 4

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Help i have 25 minutes to turn in

Zielflug [23.3K]

5/1? Im not sure if i am right

7 0

3 years ago

A fried chicken franchise finds that the demand equation for its new roast chicken product, "Roasted Rooster," is given by p = 4

LUCKY_DIMON [66]

Answer:

1. $q=(\dfrac{45}{p})^{\frac{2}{3}}$

2. $E_d=-\dfrac{2}{3}$

Step-by-step explanation:

The given demand equation is

$p=\dfrac{45}{q^{1.5}}$

where p is the price (in dollars) per quarter-chicken serving and q is the number of quarter-chicken servings that can be sold per hour at this price.

Part 1 :

We need to Express q as a function of p.

The given equation can be rewritten as

$q^{1.5}=\dfrac{45}{p}$

Using the properties of exponent, we get

$q=(\dfrac{45}{p})^{\frac{1}{1.5}}$ $[\because x^n=a\Rightarrow x=a^{\frac{1}{n}}]$

$q=(\dfrac{45}{p})^{\frac{2}{3}}$

Therefore, the required equation is $q=(\dfrac{45}{p})^{\frac{2}{3}}$ .

Part 2 :

$q=(45)^{\frac{2}{3}}p^{-\frac{2}{3}}$

Differentiate q with respect to p.

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{2}{3}-1}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{5}{3}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})$

Formula for price elasticity of demand is

$E_d=\dfrac{dq}{dp}\times \dfrac{p}{q}$

$E_d=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{(45)^{\frac{2}{3}}p^{-\frac{2}{3}}}$

Cancel out common factors.

$E_d=(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{p^{-\frac{2}{3}}}$

Using the properties of exponents we get

$E_d=-\dfrac{2}{3}(p^{-\frac{5}{3}+1-(-\frac{2}{3})})$

$E_d=-\dfrac{2}{3}(p^{0})$

$E_d=-\dfrac{2}{3}$

Therefore, the price elasticity of demand is -2/3.

3 0

3 years ago

A model of a skyscraper uses the scale of 2 inches = 45 feet. If the actual skyscraper is 992 feet tall, how tall is the model?

kvasek [131]

Answer:

44.08 or 44.1

Step-by-step explanation:

OK so the basics of this question is that for every 45 feet of the actual skyscraper we have 2 inches in the model. The first thing we do is divide 992/45 which equals 22.04. Know if this was 1 inch for every 45 feet we would be done however we need to multiply this number by 2 to get our answer so 22.04*2 =44.08

8 0

3 years ago

A small painting has an area of 400 cm^2. The length is 4 more than twice the width. Find the dimensions of the pool. Solve by c

anygoal [31]

A = l*w
l = 2w + 4
400 = (2w + 4)*w
0 = 2w^2 + 4w - 400

Then use the quadratic equation where a=2, b=4, and c=-400.

w = <span>13.2
l = 30.4
</span>

6 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA POINTS*.. <br> IM GIVING 40 POINTS !! DONT SKIP :((.

oksian1 [2.3K]

m = 1.49

b = 5.50

equation y = 1.49x + 5.50

Non-proportional

Positive Slope

8 0

3 years ago