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Salsk061 [2.6K]
3 years ago
10

A flask contains 5.0g of neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the v

olume of the neon gas
Chemistry
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

The volume of the neon gas is 17.07 L.

Explanation:

The ideal gas equation describes the relationship among the four variables  P, V, T, and n. An ideal gas<u> is a hypothetical gas whose pressure-volume-temperature  behavior can be completely accounted for by the ideal gas equation</u>.

In order to calculate the volume, first we need to convert the grams of neon to moles:

28.18 g Ne ------ 1 mol Ne

5.0 g Ne---------- <u>x= 0.25 mol Ne</u>

Now, using the ideal gas equation we calculate the volume:

pV= nRT

V= nRT ÷ p

V= (0.25 mol × 0.082 L.atm/mol.K × 308.15 K ÷ 0.37 atm

V= 17.07 L

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The rate of generation of neutrons need to be controlled in the reaction to have a controlled chain reaction which is suitable for generating electricity.

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vovangra [49]
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A balloon has a pressure of 3.1 atm at a volume of 155 ml. if the temperature is held constant, what is the volume (ml) if the p
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Answer:

45.8 mL

Explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm                        P₂ = 10.5 atm

V₁ = 155 mL                       V₂ = ? mL

P₁V₁ = P₂V₂                                                 <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂                <----- Insert values

480.5 = (10.5 atm)V₂                                  <----- Multiply 3.1 and 155

45.8 = V₂                                                    <----- Divide both sides by 10.5

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