The empirical formula CH₂ has a mass [(12 × 1) + (1 × 2)] = 14 g/mol
If the empirical formula is 14 g/mol,
and the molecular formula is ~140 g/mol
Then the multiple is = 140 g/mol ÷ 14 g/mol
= 10
Therefor the molecular formula is 10(CH₂) = <span>C</span>₁₀<span>H</span>₂₀<span> </span>
Answer:
C. An electronegativity difference of less than 1.7 between the atoms
Explanation:
I have no idea but that’s correct I just answered it on apex
Answer:
CHCL3= 11.73 mL
CHBr3= 8.268 mL
Explanation:
Let x be the mL of CHCl3 and y be the mL of CHBr3, then we have:
y+x = 20 mL
1.492x+2.89y=2.07* 20.0 mL
Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol
Find the molar mass
2Na = 23 * 2 = 46 grams
1S = 32 * 1 = 32 grams
O4 = 16 * 4 = 64 grams
Total = 142 grams / mol
Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???
given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams.
85.2 are in a 2 L solution that has a concentration of 0.6 mol/L
