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3 years ago

Describe the relationship between hydrogen oxygen and water

1 answer:

6 0

Hydrogen is composed of H atom and oxygen is composed of O atom. For water, it is composed by both H and O atom. If you burn hydrogen in oxygen, you can get water. And if you electrolysis water, you can get hydrogen and oxygen.

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Often computers are described as not intelligent. How does the mindstorm prove this?

n200080 [17]

Answer:

CH4+2O2-->2H2O+CO2 chemical reaction

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3 years ago

Please help..... who is up for a zoom to help me with balancing equations

Alex787 [66]

Answer:

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3 years ago

Read 2 more answers

Provide a balanced molecular equation, total ionic, and net ionic equation for sodium phosphate and zinc acetate.

vivado [14]

Answer: Balanced molecular equation :

$2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)$

Total ionic equation:

$6Na^+(aq)+3PO_4^{2-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)$

The net ionic equation:

$2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)$

Explanation:

Complete ionic equation : In complete ionic equation, all the substances that are strong electrolyte are present in an aqueous state as ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When sodium phosphate and zinc acetate then it gives zinc phosphate and sodium acetate as product.

The balanced molecular equation will be,

$2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)$

The total ionic equation in separated aqueous solution will be,

$6Na^+(aq)+2PO_4^{3-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)$

In this equation, and are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)$

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2 years ago

I Need Help With This I’m so Confused on it.

ss7ja [257]

Answer:

Explanation:

yeah........

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3 years ago

Determine the full electron configurations:<br><br> 1. K+ (Z=19)<br><br> 2. Zn2+ (Z=30)

mixas84 [53]

Answer:

1= K⁺= (Z=19) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰

2 = Zn²⁺= (Z = 30) =1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰, 3d¹⁰

Explanation:

When an atom lose or gain the electron ions are formed. There are two types of ions cation and anion.

Cation are formed when atom lose the electron.

Anion are formed when an atom gain the electron.

In given question potassium loses its valance electron and form K⁺ cation. Thus its electronic configuration will be written as,

₁₉K⁺ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰

While the electronic configuration of potassium in neutral form is:

₁₉K = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹

The atomic number of zinc is 30 and its electronic configuration is:

₃₀Zn= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s², 3d¹⁰

When zinc atom loses its 2 valance electrons the electron configuration will be,

₃₀Zn²⁺= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰, 3d¹⁰

7 0

3 years ago