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katen-ka-za [31]
4 years ago
14

Which of the following z-values, standard deviations, and sample sizes produce a margin of error of 0.95?

Mathematics
2 answers:
Andre45 [30]4 years ago
7 0

Answer:

B. z = 2.14; s = 4; n = 81

Step-by-step explanation:

s2008m [1.1K]4 years ago
3 0

Answer:

B. z = 2.14; s = 4; n = 81

Step-by-step explanation:

We know that,

\text{Margin of error}=z\cdot \dfrac{\sigma}{\sqrt n}

Putting the values,

z = 2.14; s = 4; n = 9

\text{Margin of error}=2.14\cdot \dfrac{4}{\sqrt 9}=2.85

z = 2.14; s = 4; n = 81

\text{Margin of error}=2.14\cdot \dfrac{4}{\sqrt{81}}=0.95

z = 2.14; s = 16; n = 9

\text{Margin of error}=2.14\cdot \dfrac{16}{\sqrt 9}=11.41

z = 2.14; s = 16; n = 81

\text{Margin of error}=2.14\cdot \dfrac{16}{\sqrt{81}}=3.80


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