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vredina [299]
3 years ago
6

3. What methods are you using to test this (or each) hypothesis?. ​

Physics
2 answers:
Gnoma [55]3 years ago
4 0

Answer:

my method is guessing it works 50% of the time :)

Explanation:

Monica [59]3 years ago
4 0

Traditional Method->>>>I'm not 100% sure of my answer but gl buddy

Step 1 Identify the Null Hypothesis and the Alternative Hypothesis

Step 2 Identify α (Level of Significance)

Step 3 Find the critical value(s)

Step 4 Find the test statistic

 For a Proportion: Hand calculation

TI 83/84 – Use 1PropZTest (See Handout H-404)

 For a population mean (with α known):

TI 83/84 - Use Z-Test (See Handout H 404)

 For a population mean (with α Not known):

TI 83/84 - Use T-Test (See Handout H-404)

Step 5 Draw a graph and label the test statistic and critical value(s)

Step 6 Make a decision to reject or fail to reject the null hypothesis

 Reject - The test statistic falls within the critical region.

 Fail to Reject - Test statistic does not fall within the critical

region.

P-Value Method:

<em>P-value is the area determined as follows:</em>

<em> Left Tail Test: p-value is the area to the left of the test statistic.</em>

<em> Right Tail Test: p-value is the area to the right of the test statistic.</em>

<em> Two Tailed Test: p-value is twice the area bounded by the test statistic</em>

<em>Make a decision to reject or fail to reject the null hypothesis:</em>

<em> Reject if p-value ≤ α</em>

<em> Fail to reject if p-value > α</em>

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A light bulb whose resistance is 240 ohms is connected to a 120 voltage source. What is the current through the bulb?
Sedaia [141]

Answer:

0.5A

Explanation:

Using R = \frac{V}{I},

R is the resistance (in Ohms)

V is the voltage (in V)

I is the current (in A)

240=\frac{120}{I}

I = 0.5A

7 0
2 years ago
A positively charged object is brought near but not in contact with the top of an uncharged gold leaf electroscope. The experime
Olin [163]

Answer:

The leaves of the electroscope move further apart.

Explanation:

This is what happens; when the positive object is brought near the top, negative charges migrating from the gold leaves to the top. This is because the negative charges in the gold are attracted by the positive charge. Thus, it leaves behind a net positive charge on the leaves, though the scope remains neutral overall. To that effect, the leaves repel each other and move apart. If a finger touches the top of the electroscope at the moment when the positive object remains near the top, it basically grounds the electroscope and thus the net positive charge in the leaves flows to the ground through the finger. However, the positive object continues to "hold" negative charges in place at the top. Ar this moment the gold leaves have lost their net positive charge, so they no longer repel, and they move closer together. If the positive object is moved away, the negative charges at the top are no longer attracted to the top, and they redistribute themselves throughout the electroscope, moving into the leaves and charging them negatively.

Thus, the leaves move apart from each other again and we now have a negatively charged electroscope. If a negatively charged object is now brought close to the top, but without touching, the negative charges already in the electroscope will be repelled down toward the leaves, thereby making them more negative, causing them to repel more, and hence move even further apart.

So, the leaves move further apart.

7 0
2 years ago
One hundred turns of insulated copper wire are wrapped into a circular coil of crosssectional area 1.20⇥103 m2. The two ends of
arsen [322]

Answer:

236.3  x 10^-^3 C

Explanation:

Given:

B(0)=1.60T and B(t)=-1.60T

No. of turns 'N' =100

cross-sectional area 'A'= 1.2 x 10^-^3m²

Resistance 'R'= 1.3Ω

According to Faraday's law, the induced emf is given by,

ℰ=-NdΦ/dt

The current given by resistance and induced emf as

I = ℰ/R

I= -NdΦ/dtR

By converting the current to differential form(the time derivative of charge), we get

\frac{dq}{dt}=  -NdΦ/dtR

dq= -N dΦ/R

The change in the flux dФ =Ф(t)-Ф(0)

therefore, dq = \frac{N}{R} (Ф(0)-Ф(t))

Also, flux is equal to the magnetic field multiplied with the area of the coil

dq = NA(B(0)-B(t))/R

dq= (100)(1.2 x 10^-^3)(1.6+1.6)/1.3

dq= 236.3  x 10^-^3 C

5 0
3 years ago
What is NOT a raw minteral used in photosyntheisis
Yuliya22 [10]
The photosynthesis equation is : 

H2O + CO2 + sunlight (energy) > C6H12O6 + O2 

So water (H2O) and carbon dioxide (CO2) are the raw materials need for photosynthesis.
6 0
3 years ago
Why might exposing astronauts to weightlessness be harmful?
love history [14]
The body doesn't have to work as hard when there's no gravity for it to work against, so it becomes accustomed to a much lower work load on every level. It leads to lower bone mass and weaker muscles, including the heart, leading to a drop in blood pressure that can eventually build up to create problems with cognitive function. After so long, minor accidents can lead to major, even life threatening problems. A simple bump that would do little more than leave a bruise on you and I can result in a broken femur bone or broken neck on an astronaut who has been exposed to a weightless environment for too long.

This is one of the several hurdles that must be overcome in order for a manned mission to Mars to succeed. Exposure to a weightless environment on the order of roughly two years for a manned Mars mission would be so degrading to the body that the rough, turbulent re-entry into Earth's atmosphere might prove to be too violent for an astronaut to survive.

The problem is bones.

On Earth, every time you do something with "impact" (like walking), there are microcracks in your bones. Calcium is used by the body to fix these cracks... and that is how the bones grow and become strong.

No weight = no impact = no cracks = no "repairs" being done by the body = the body gets rid of un-neede calcium and bones become brittle and weak.

There are some other operations in the body that require gravity as a "director", or resistance to movement as a driver of change (think of muscles in the legs, when there is no need to walk).

The organ themelves are (generally) OK since many things can work in any orientation.
5 0
2 years ago
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