Answer:
I= 20 i {N.s}
Explanation:
In order to obtain the impulse on the 2 kg ball, you have to apply the equation of Impulse:
I=FΔt
Where I is the impulse vector, F is the net force and Δt is the interval of time when the force is applied.
In this case:
Δt=0.01 s
F= 2000 i N
where i is the unit vector in the x direction.
Replacing the values in the formula:
I=(2000)(0.01)i
Therefore:
I= 20 i {N.s}
The penny will reach terminal velocity at 50 ft. Then it will travel 25 mph till it reaches ground.
Answer:
80.4 N
Explanation:
As the block is at rest on the slope, it means that all the forces acting on it are balanced.
We are only interested in the forces that act on the block along the direction perpendicular to the slope. Along this direction, we have two forces acting on the block:
- The normal reaction N (contact force), upward
- The component of the weight of the block,
, downward, where m is the mass of the block, g is the gravitational acceleration and
is the angle of the incline
Since the block is in equilibrium along this direction, the two forces must balance each other, so they must be equal in magnitude:

And by substituting the numbers into the equation, we find the size of the contact force normal to the slope:

Answer:
w = 73 N
Explanation:
Since the box is held by the ropes it means that the resulting tension is equal to the weight of the box
T_res = w
Now, the resulting tension is a combination of the tension of each rope.
Since we want to find the vertical component we must multiply by the cosine of 30 degrees the value of T
T_res = T*cos(30) + T*cos(30)
T_res = 2*(42 N)*(0.866)
T_res = 72.746 N
T_res = w = 72.746 N