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asambeis [7]
3 years ago
14

A hockey puck initially travelling to the right at 34 m/s. It moves for 7 before

Physics
1 answer:
goldfiish [28.3K]3 years ago
3 0

Answer:

x=119m

Explanation:

Hello,

In this case, since the hockey puck was moving at 34 m/s and suddenly stopped (final velocity is zero) in 7 seconds, we can first compute the acceleration via:

a=\frac{v_f-v_o}{t}=\frac{0m/s-34m/s}{7s}\\  \\a=-4.86m/s^2

In such a way, we can compute the displacement via:

x=\frac{v_f^2-v_o^2}{2a}\\ \\x=\frac{0^2-(34m/s)^2}{2*-4.86m/s^2}\\ \\x=119m

Best regards.

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Answer:

I= 20 i {N.s}

Explanation:

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In this case:

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Since the block is in equilibrium along this direction, the two forces must balance each other, so they must be equal in magnitude:

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