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aniked [119]
3 years ago
13

A projectile is fired straight upward from the Earth's surface at the South Pole with an initial speed equal to one third the es

cape speed. (The radius of the Earth is 6.38 106 m.)
Physics
1 answer:
7nadin3 [17]3 years ago
3 0
What is the question? if you are looking for the initial velocity of the projectile, then V escape of Earth = 11.2 km / s. divided by three
Vi = 3.73 km/s
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The steps in the heating of a metal seat in a park are listed below: Step 1: Heat travels from the sun to Earth Step 2: Heat tra
I am Lyosha [343]

The steps in the heating of a metal seat in a park are:

Step 1: Heat travels from the sun to Earth

Step 2: Heat travels through atmosphere to the top of the seat

Step 3: Heat from the top of the seat travels through the seat to the lower parts of the seat.

-- Heat is transferred by radiation in Step 1 and Step 2. <em>(B)</em>

-- From the top of the seat to the bottom, heat is transferred by conduction.  

There's no convection happening anywhere in the park-hot-seat scenario.

3 0
3 years ago
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Two boats leave the same port at the same time, with boat A traveling north at 15 knots (nautical miles per hour) and boat B tra
Mrrafil [7]

Answer:

The chance in distance is 25 knots

Explanation:

The distance between the two particles is given by:

s^2 = (x_A - x_B)^2+(y_A - y_B)^2  (1)

Since A is traveling north and B is traveling east we can say that their displacement vector are perpendicular and therefore (1) transformed as:

s^2 = x_B^2+y_A^2 (2)

Taking the differential with respect to time:

\displaystyle{2s\frac{ds}{dt}= 2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt}}  (3)

where \displaystyle{\frac{dx_B}{dt}}=v_B and \displaystyle{\frac{dx_A}{dt}}=v_A are the respective given velocities of the boats. To find s and x_B we make use of the given position for A, y_A=30, the Pythagoras theorem and the relation between distance and velocity for a movement with constant velocity.

\displaystyle{y_A = v_A\cdot t\rightarrow t = \frac{y_A}{v_A}=\frac{30}{15}=2 h

with this time, we know can now calculate the distance at which B is:

\displaystyle{x_B = v_B\cdot t= 20 \cdot 2 = 40\ nmi

and applying Pythagoras:

\displaystyle{s = \sqrt{x_B^2+y_A^2}=\sqrt{30^2 + 40^2}=\sqrt{2500}=50}

Now substituting all the values in (3) and solving for  \displaystyle{\frac{ds}{dt} } we get:

\displaystyle{\frac{ds}{dt} = \frac{1}{2s}(2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt})}\\\displaystyle{\frac{ds}{dt} = 25 \ knots}

4 0
3 years ago
What do understand by the efficiency of a machine? By using a block and tackel a man can raise a load of 720 N by an effort of 1
motikmotik

Answer:

Efficiency of a machine is how well the machine works and what the machine is capable of doing.

Mechanical advantage=Load/Effort.

720/180=4

6 0
3 years ago
What does the term "heat capacity" refer to?
kenny6666 [7]

Answer:

option C is correct

.............,

4 0
2 years ago
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You observe a plane approaching overhead and assume that its speed is 600 miles per hour. The angle of elevation of the plane is
scZoUnD [109]

Answer:4.34 miles

Explanation:

first  Elevation =19^{\circ}

After 1 minute Elevation changes to 59^{\circ}

Ditsance travelled in 1 minute =600\times \frac{1}{60}=10 mile

Now

tan59=\frac{H}{x}

H=xtan59

tan19=\frac{H}{10+x}

H=\left ( 10+x\right )tan19

Equating H

we get

1.319x=10tan19

x=2.61 miles

H=2.61\times tan59=4.34 miles

4 0
3 years ago
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