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pickupchik [31]
1 year ago
8

An aluminum block of mass 12.00 kg is heated from 20 c to 118 c. if the specific heat of aluminum is 913 j-1 kg k-1 then how muc

h energy is required?
Physics
1 answer:
Jobisdone [24]1 year ago
6 0

Answer:

107 kJ

Explanation:

12.00 kg * 913 J /kg-C * (118-20)°C        ( I corrected spec heat units)

                    ( a  C degree change is the same as a kelvin change)

                   = 1 073 688 J   = 107 kJ   ( three sig digits)

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A force of 1.5 × 102 N is exerted on a charge of 1.4 × 10–7 C that is traveling at an angle of 75° to a magnetic field.
Marysya12 [62]

Option (B) is correct.The magnetic field strength=8.5 x 10² T

Explanation:

the magnetic force Fm is given by

Fm= q V B sinθ

q= charge=1.4 x 10⁻⁷ C

v= velocity= 1.3 x 10⁶ m/s

B= magnetic field strength

Fm= magnetic force= 1.5 x 10² N

θ=75°

so 1.5 x 10²=(1.4 x 10⁻⁷) (1.3 x 10⁶ ) (B) sin75

B=8.5 x 10² T

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3 years ago
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Which of the following describes electric change?
DedPeter [7]
It would be B, like charges repel and unlike charges attract.
8 0
3 years ago
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what is the kinetic energy of an object that as a mass of 12 kilograms and moves with the velocity of 10 m/s
Galina-37 [17]

Answer:

120 m/s

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3 years ago
Study the image of the moving car.
gayaneshka [121]

Answer:

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Explanation:

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2 years ago
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Two Physics quick help
Free_Kalibri [48]

Answer:

21.3 V, 1.2 A

Explanation:

1.

These resistors are in series, so the net resistance is:

R = R₁ + R₂ + R₃

R = 20 + 30 + 45

R = 95

So the current is:

V = IR

45 = I (95)

I = 9/19

So the voltage drop across R₃ is:

V = IR

V = (9/19) (45)

V ≈ 21.3 V

2.

First, we need to find the equivalent resistance of R₂ and R₃, which are in parallel:

1/R₂₃ = 1/R₂ + 1/R₃

1/R₂₃ = 1/10 + 1/10

R₂₃ = 5

Now we find the overall resistance by adding the resistors in series:

R = R₁ + R₂₃ + R₄

R = 10 + 5 + 10

R = 25

So the current through R₁ is:

V = IR

30 = I (25)

I = 1.2 A

7 0
3 years ago
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