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liraira [26]
3 years ago
9

Elle ate 12 grapes. Riley ate 3 more grapes than Erica. How many grapes did both girls eat?​

Mathematics
1 answer:
raketka [301]3 years ago
5 0

Answer:

27

Step-by-step explanation:

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Write an equation for the proportional relationship shown in the table.
VladimirAG [237]

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Answer:

  y = 38x

Step-by-step explanation:

The constant of proportionality (k) is the value of y when x=1. The table shows that to be 38. Then the equation is ...

  y = kx

  y = 38x

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3 years ago
What is the solution to the equation<br><br>1+1
sveta [45]

Answer:

2

Step-by-step explanation:

but I would personally say FISH

8 0
3 years ago
Dalia bought a few swirl marbles and divided it equally among four of her friends
Gennadij [26K]

Answer:

16 ang answer

Step-by-step explanation:

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6 0
2 years ago
JK is formed by J(-12,3) and K(8,-5). If line r is the perpendicular bisector of JK, write an equation for r in slope-intercept
dem82 [27]

Answer:

  • y = 5/2x + 4

Step-by-step explanation:

<u>Midpoint of JK:</u>

  • x = (-12 + 8)/2 = -4/2 = -2
  • y = (3 - 5)/2 = -2/2 = -1

<u>Slope of the line JK:</u>

  • m = (-5 - 3)/(8 - (-12)) = -8/20 = -2/5

Perpendicular lines have negative reciprocal slopes.

So the line r has a slope 5/2 and passes through the point (-2, -1)

<u>Equation of r:</u>

  • y = 5/2x + b
  • -1 = 5/2(-2) + b
  • -1 = -5 + b
  • b = 5 - 1
  • b = 4

<u>So the equation is:</u>

  • y = 5/2x + 4
3 0
3 years ago
Question part points submissions used use newton's method with the specified initial approximation x1 to find x3, the third appr
serious [3.7K]

Set f(x)=2x^3-3x^2+2. Find the tangent line \ell_1(x) to f(x) at the point when x=x_1:

f'(x)=6x^2-6x\implies f'(x_1)=12 (slope of \ell_1)

\implies\ell_1(x)=12(x-x_1)+f(x_1)=12(x+1)-3=12x+9

Set x_2=-\dfrac9{12}, the root of \ell_1(x). The tangent line \ell_2(x) to f(x) at x=x_2 has slope and thus equation

f'(x_2)=\dfrac{63}8\implies\ell_2(x)=\dfrac{63}8\left(x+\dfrac9{12}\right)-\dfrac{17}{32}=7x+\dfrac{151}{32}

which has its root at x_3=-\dfrac{151}{224}\approx-0.6741.

(The actual value of this root is about -0.6777)

5 0
3 years ago
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