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Katyanochek1 [597]

4 years ago

12

When enamel is remineralized with fluoride

1 answer:

WITCHER [35]4 years ago

6 0

<h2>The required "option is d)".</h2>

Explanation:

Remineralization of enamel is a natural process and is of the same color.
The saliva contains calcium, phosphate, and fluoride which helps in the neutralisation of acids present in food.
Remineralization helps in improving the strength and functioning of the tooth by replacing calcium ions and flouride ions which were removed by demineralization.
It helps in prevention of cavity formation in teeth and strengthens the teeth by replacing loss of calcium ions, phosphate ions, and fluoride by fluorapatite crystals that are more resistant to acids.
Hence, the remineralized crystal is more resistant to acids.

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Burning fossil fuels is like letting go of a slingshot because both change potential energy into ___ energy.

Yuliya22 [10]

The answer is Mechanical energy

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3 years ago

Helium is mixed with oxygen gas for deep-sea divers. Calculate the percent by volume of oxygen gas in the mixture if the diver h

kvasek [131]

Answer : The percent by volume of oxygen gas in the mixture is, 5.3 %

Explanation :

According to the Raoult's law,

$p^o_A=X_A\times p_A$

where,

$p_A$ = total partial pressure of solution = 3.8 atm

$p^o_A$ = partial pressure of oxygen = 0.20 atm

$X_A$ = mole fraction of oxygen = ?

Now put all the given values in this formula, we get:

$p^o_A=X_A\times p_A$

$0.20atm=X_A\times 3.8atm$

$X_A=0.0526$

Now we have to calculate the percent by volume of oxygen gas in the mixture.

The mole percent of oxygen gas = $0.0526\times 100=5.3\%$

As we know that, there is a direct relation between the volume of moles.

So, mole percent of oxygen gas = volume percent of oxygen gas

Volume percent of oxygen gas = $0.0526\times 100=5.3\%$

Therefore, the percent by volume of oxygen gas in the mixture is, 5.3 %

5 0

4 years ago

A solution was made by mixing 60.5 g of glucose (C6H12O6) with enough water to make 325 ml of solution. What is the percent (mas

IgorC [24]

mass percent concentration = 15.7 %

molar concentration of glucose solution 1.03 M

Explanation:

To calculate the mass percent concentration of the solution we use the following formula:

concentration = (solute mass / solution mass) × 100

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solution mass = solute mass + water mass

solution mass = 60.5 + 325 = 385.5 g (I used the assumption that the solution have a density of 1 g/mL)

concentration = (60.5 / 385.5) × 100 = 15.7 %

Now to calculate the molar concentration (molarity) of the solution we use the following formula:

molar concentration = number of moles / volume (L)

number of moles = mass / molecular weight

number of moles of glucose = 60.5 / 180 = 0.336 moles

molar concentration of glucose solution = 0.336 / 0.325 = 1.03 M

Learn more about:

molarity

brainly.com/question/10053901

#learnwithBrainly

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if during the interaction of 36.5 g of hydrochloric acid with magnesium 137 kg of joules energy are released, how much energy wo

svetoff [14.1K]

Explanation:

ANSWER

The molarity =

molecularweight

density×purity×10

=

36.5

1.18×36.5×10

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