Question

Calculate the volume in milliliters of a 0.51M barium chloride solution that contains 75.0mmol of barium chloride BaCl2. Be sure your answer has the correct number of significant digits.

Answer 1

Answer:

0.15 L= 150 ml

Explanation:

barium choride = BaCl₂

0.51 M = 0.51 mol BaCl₂/ 1 L solution

1 mol is equal to 1000 times a mmol:

0.51 mol = 0.51 x 10³ mmol= 510 mmol

As you know that the solution has 510 mmol BaCl₂ per liter, you can use the following simple calculation to obtain the volume in which there are 75 mmol BaCl₂:

510 mmol BaCl₂ ------ 1 L

75 mmol BaCl₂--------- X

X= $\frac{75 mmol x 1 L}{510 mmol}$ = 0.147 L ≈ 0.15 L