<span>They both have charged particles
They have the same attractive forces between particles
They have the same space between particles
They create magnetic and electric fields</span>
Answer:
ΔG = - 442.5 KJ/mol
Explanation:
Data Given
delta H = -472 kJ/mol
delta S = -108 J/mol K
So,
delta S = -0.108 J/mol K
delta Gº = ?
Solution:
The answer will be calculated by the following equation for the Gibbs free energy
G = H - TS
Where
G = Gibbs free energy
H = enthalpy of a system (heat
T = temperature
S = entropy
So the change in the Gibbs free energy at constant temperature can be written as
ΔG = ΔH - TΔS . . . . . . (1)
Where
ΔG = Change in Gibb’s free energy
ΔH = Change in enthalpy of a system
ΔS = Change in entropy
if system have standard temperature then
T = 273.15 K
Now,
put values in equation 1
ΔG = (-472 kJ/mol) - 273.15 K (-0.108 KJ/mol K)
ΔG = (-472 kJ/mol) - (-29.5 KJ/mol)
ΔG = -472 kJ/mol + 29.5 KJ/mol
ΔG = - 442.5 KJ/mol
1. From the balanced equation given above, the ratio of the number of moles of the hydrocarbon and oxygen is equal to 2/7. Given that there are 2 moles of oxygen,
moles hydrocarbon = (2 moles O2)(2 moles HC / 7 moles oxygen)
Simplifying,
moles HC = 4/7 or 0.57 moles HC
Answer: 0.57 moles HC
2. The calculation for the mass of water is shown below with the dimensional analysis and conversion factors,
(30 g C2H6)1 mole C2H6/30 g C2H6)(6 molesH2O/2 moles C2H6)(18 g H2O/1 mole C2H6)
Simplifying,
mass = 54 grams of water
Answer:
A) the temperature of the water will increase.
Explanation:
Consider, first, the dissolution of anhydrous calcium chloride, CaCl2 in water. CaCl2 is a very water soluble ionic compound that, in solution, dissociates into the component ions, Ca2 + and Cl-, which interact strongly with water molecules.
The thermochemical equation that represents the process of dissolution of CaCl2 (s) indicates that it is a strongly exothermic process:
CaCl2(s) --> Ca+2(aq) + 2Cl- (aq) ΔH = -82.8 kJ
Therefore, dissolving CaCl2 in water will produce the release of energy in the form of heat (82.8 kJ per mole of dissolved CaCl2)
