Question

A sample of gas occupies 250 mL at STP. What is the temperature if the gas expands to 1500 mL at a pressure of 0.500 atm? *

Answer 1

Answer:

819 K

Explanation:

Given data

• Initial pressure (P₁): 1 atm (standard pressure)

• Initial volume (V₁): 250 mL

• Initial temperature (T₁): 273.15 K (standard temperature)

• Final pressure (P₂): 0.500 atm

• Final volume (V₂): 1500 mL

• Final temperature (T₂): ?

We can find the final temperature using the combined gas law.

$\frac{P_1 \times V_1 }{T_1} = \frac{P_2 \times V_2 }{T_2}\\T_2 = \frac{P_2 \times V_2 \times T_1 }{P_1 \times V_1} = \frac{0.500atm \times 1500mL \times 273.15K }{1atm \times 250mL}=819K$