Answer:
The correct answer for the given question is " The Code fragment A runs fastly than the code fragment of B".
Explanation:
In this question there are some information is missing i. e options. The question does not give any options. The options for the given question is given below
(A.) The Code fragment A runs fastly than the code fragment of B.
(B.) The Code fragment B runs fastly than code fragment of A.
(C) The Code fragment A runs as fastly as code fragment of B.
So we conclude the answer i.e option(A) because As given in the question list1 is a MyArrayList and list2 is a MyLinkedList. , in list1 we fetching the data easily and fastly means that it remove the data easily as compare to list2 As MyArrayList is storing the list only and also we can fetch the data easily manner.
The list2 is an object of MyLinkedList means that it manipulating the data fastly as compared to MyArrayList but if we compared the fetching of data then MyArrayList is a better option so the code fragment runs fastly then code fragmented B.
Answer:
Behaviour
Style
Structure
Explanation:
Above are the three primary separation of concerns for a web application at client side.
Structure --> we can define the structure of the application at client side using HTML
style-->style is used to give some styling information like font,color,headings so on at client side .In general we use CSS to do this at client side
Behaviour--> it actually defines the functionality of the elements at client side like when we click button what it should do.We will use JavaScript to define the behaviours at client side
Network issues; screen resolution and volume issues
Answer:
方法/步骤
右键单击以选择此计算机，然后有一个菜单来选择属性。
选择后，打开属性面板以找到我们的高级系统设置。
打开后，我们在系统设置下找到高级设置。
打开后，我们看到下面有一个环境变量选项。
打开后，我们在右下角看到一个删除选项。
单击删除到，在右下角后单击删除，然后单击确定的选项。 ...
本文未经授权摘自百度经验
Answer:
words.hasNext()
Explanation:
Given the code snippet below:
- while (inputFile.hasNextLine()) {
- String word = "";
- String line = inputFile.nextLine();
- Scanner words = new Scanner(line);
- while (words.hasNext()) {
- word = words.next();
- }
- System.out.println(word); }
- }
We have a inputFile Scanner object that can read data from a text file and we presume the inputFile has read several rows of data from the text file. So long as there is another line of input data available, the outer while loop will keep running. In each outer loop, one line of data will be read and assign to line variable (Line 3). Next, there is another Scanner object, words, which will take the current line of data as input. To get the last word of that line, we can use hasNext() method. This method will always return true if there is another tokens in its input. So the inner while loop will keep running so long as there is a token in current line of data and assign the current token to word variable. The word will hold the last token of current line of data upon exit from the inner loop. Then we can print the output (Line 8) which is the last word of the current line of data.
