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3 years ago

this is a non graded disscussion i want to fill out it is just a worksheet to help me get better 30 points

Physics

1 answer:

poizon [28]3 years ago

3 0

Answer:

1.) 30m/s

2) 5m/s

3) 40Hz

4) 400Hz

5) 300Hz

6) 0.77m

7) 0.386m

8) 0.625m

9) 100m/s

10) 50m/s

Explanation:

The speed of a wave (V) equals :

V = fλ ; where f = frequency, λ = wavelength

1.) f = 100Hz, λ = 0.30m

v = 100 * 0.30 = 30m/s

2) f = 50Hz λ = 0.10m

v = 50 × 0.10 = 5m/s

3) v = 20m/s, λ= 0.5m

f = v / λ

f = 20 / 0.5 = 40Hz

4) v = 80m/s, λ= 0.2m

f = 80/0.2 = 400Hz

5) v = 120m/s, λ = 0.4m

f = 120 / 0.4 = 300Hz

6) v = 340m/s, f = 440Hz

λ = v / f ; 340 / 440 = 0.77m

7) v = 340m/s, f = 880Hz

λ = 340 / 880 = 0.386m

8) v = 250m/s, f = 400

λ = 250 / 400 = 0.625m

9) f = 50Hz, λ = 2m

v = 50 × 2 = 100m/s

10) f = 100Hz, λ = 0.5m

v = 100 × 0.5 = 50m/s

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v²/36 = 9.8 [(0.4695 + 0.87*0.8829) - (0.8829 - 0.87*0.4695)]

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3 years ago

You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 294.0 kPa when the ther

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Answer: 361° C

Explanation:

Given

Initial pressure of the gas, P1 = 294 kPa

Final pressure of the gas, P2 = 500 kPa

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Final temperature of the gas, T2 = ?

Let us assume that the gas is an ideal gas, then we use the equation below to solve

T2/T1 = P2/P1

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3 years ago

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Answer:

The speed of the heavier fragment is 0.335c.

Explanation:

Given that,

Mass of the lighter fragment $M_{l}=2.90\times10^{-28}\ kg$

Mass of the heavier fragment $M_{h}=1.62\times10^{-27}\ Kg$

Speed of lighter fragment = 0.893c

We need to calculate the speed of the heavier fragment

Let v is the speed of the second fragment after decay

Using conservation of relativistic momentum

$0=\drac{m_{1}v_{1}}{\sqrt{1-\dfrac{v_{1}^2}{c^2}}}-\drac{m_{2}v_{2}}{\sqrt{1-\dfrac{v_{1}^2}{c^2}}}$

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$\dfrac{v_{2}}{1-\dfrac{v_{2}^{2}}{c^2}}=(0.355c)^2$

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3 years ago

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3 years ago