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worty [1.4K]
3 years ago
9

Water and cooking oil have the same density because they're both liquids. TRUE OR FALSE

Physics
2 answers:
ki77a [65]3 years ago
5 0

Answer:

False

Explanation:

Not all liquids have the same density. We know for example that oil float on the water surface because it has less density than the water.

marissa [1.9K]3 years ago
5 0

The given statement “Water and cooking oil have the same density because they're both liquids" is false.

Answer: Option 2

<u>Explanation: </u>

It’s not necessary to have same densities if two elements are in the same state of matter. Just like solids, liquids also have different level of densities.

If you add some vegetable oil in water, you’ll see that oil will float upon the surface of the water. In fact, different types of oils and liquids float in water according to their densities that are different from one another.

Liquids have different densities because of the atomic structure they have and their respective particles mass which forms their density being the ratio of their mass and volume. Thus, liquids or air having heavier density float lower than those having lighter density.

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A place kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. half the crowd hopes the ball will clear
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<span>The ball clears by 11.79 meters Let's first determine the horizontal and vertical velocities of the ball. h = cos(50.0)*23.4 m/s = 0.642788 * 23.4 m/s = 15.04 m/s v = sin(50.0)*23.4 m/s = 0.766044 * 23.4 m/s = 17.93 m/s Now determine how many seconds it will take for the ball to get to the goal. t = 36.0 m / 15.04 m/s = 2.394 s The height the ball will be at time T is h = vT - 1/2 A T^2 where h = height of ball v = initial vertical velocity T = time A = acceleration due to gravity So plugging into the formula the known values h = vT - 1/2 A T^2 h = 17.93 m/s * 2.394 s - 1/2 9.8 m/s^2 (2.394 s)^2 h = 42.92 m - 4.9 m/s^2 * 5.731 s^2 h = 42.92 m - 28.0819 m h = 14.84 m Since 14.84 m is well above the crossbar's height of 3.05 m, the ball clears. It clears by 14.84 - 3.05 = 11.79 m</span>
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3 years ago
Science: Could a dysfunction or disease of the nervous system affect other body systems, such as the muscular or digestive syste
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You may experience the sudden onset of one or more symptoms, such as: Numbness, tingling, weakness, or inability to move a part or all of one side of the body (paralysis). Dimness, blurring, double vision, or loss of vision in one or both eyes. Loss of speech, trouble talking, or trouble understanding speech.

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2 years ago
According to the momentum principle, the change in momentum of an object equals the impulse, which depends on______
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Answer: The momentum principle depends on MASS and VELOCITY.

Explanation:

The momentum principle states that net force changes the the momentum of an object where momentum is the product of the MASS of the body and it's VELOCITY.

Thus, momentum = mass(kg) ×velocity( m/s)= kgm/s ( derived unit)

Also to determine the rate of change of momentum;

Mass=m, initial velocity =u, final velocity = V and time =t

Initial momentum = mu

Final momentum = mv

Change in momentum = mv - mu

= m( v- u)

Rate of change of momentum=

m( v -u)/t --> equation 1

But V = u + at

Hence, a = v -u/t

Substitute for v -u/ t in equation 1

F = Kma, where k is constant and has the value of 1.

Therefore F = ma

Newton is the SI unit if force. It is defined as the force which gives a mass of 1kg an acceleration of 1 m/s².

IMPULSE is defined as the change of momentum of a body (mv-mu) or the product of force and time.

Thus impulse = force × time = m (v-u)

The unit is Ns ( Newton seconds) which is the same as change in momentum.

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2 years ago
An electron with velocity v = 1.0 ´ 106 m/s is sent between the plates of a capacitor where the electric field is E = 500 V/m. I
oksano4ka [1.4K]

Answer:

The deviation in path is 4.39 \times 10^{-3}

Explanation:

Given:

Velocity v = 1 \times 10^{6} \frac{m}{s}

Electric field E = 500 \frac{V}{m}

Distance x = 1 \times 10^{-2} m

Mass of electron m = 9.1 \times 10^{-31} kg

Charge of electron q = 1.6 \times 10^{-19} C

Time taken to travel distance,

    t = \frac{x}{v}

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    t = 10^{-8} sec

Acceleration is given by,

  F = qE

ma = qE

   a = \frac{qE}{m}

   a = \frac{1.6 \times 10^{-19} \times 500}{9.1 \times 10^{-31} }

   a = 8.77 \times 10^{13} \frac{m}{s^{2} }

For finding the distance, we use kinematics equations.

   y = vt + \frac{1}{2}  at^{2}

Where v = 0 because here initial velocity zero

   y = \frac{1}{2} at^{2}

   y = \frac{1}{2} \times  8.77 \times 10^{13 } \times (10^{-2} )^{2}

   y = 4.39 \times 10^{-3} m

Therefore, the deviation in path is 4.39 \times 10^{-3}

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