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3 years ago

Water and cooking oil have the same density because they're both liquids. TRUE OR FALSE

Physics

2 answers:

ki77a [65]3 years ago

5 0

Answer:

False

Explanation:

Not all liquids have the same density. We know for example that oil float on the water surface because it has less density than the water.

marissa [1.9K]3 years ago

5 0

The given statement “Water and cooking oil have the same density because they're both liquids" is false.

Answer: Option 2

<u>Explanation: </u>

It’s not necessary to have same densities if two elements are in the same state of matter. Just like solids, liquids also have different level of densities.

If you add some vegetable oil in water, you’ll see that oil will float upon the surface of the water. In fact, different types of oils and liquids float in water according to their densities that are different from one another.

Liquids have different densities because of the atomic structure they have and their respective particles mass which forms their density being the ratio of their mass and volume. Thus, liquids or air having heavier density float lower than those having lighter density.

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A 45 kg bear slides, from rest, 11 m down a lodgepole pine tree, moving with a speed of 5.8 m/s just before hitting the ground.

Viefleur [7K]

Answer:

Explanation:

a )

change in the gravitational potential energy of the bear-Earth system during the slide = mgh

= 45 x 9.8 x 11

= 4851 J

b )

kinetic energy of bear just before hitting the ground

= 1/2 m v²

= .5 x 45 x 5.8²

= 756.9 J

c ) If the average frictional force that acts on the sliding bear be F

negative work done by friction

= F x 11 J

then ,

4851 J - F x 11 = 756.9 J

F x 11 = 4851 J - 756.9 J

= 4094.1 J

F = 4094.1 / 11

= 372.2 N

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2 years ago

A firefighting crew uses a water cannon that shoots water at 25.0 m/s at a fixed angle of 53.0° above the horizontal. The fire-f

zysi [14]

Answer:

8.8 m and 52.5 m

Explanation:

The vertical component and horizontal component of water velocity leaving the hose are

$v_v = vsin(\alpha) = 25sin(53^0) = 25*0.8 = 19.97 m/s$

$v_h = vcos(\alpha) = 25cos(53^0) = 25*0.6 = 15 m/s$

Neglect air resistance, vertically speaking, gravitational acceleration g = -9.8m/s2 is the only thing that affects water motion. We can find the time t that it takes to reach the blaze 10m above ground level

$s = v_vt + gt^2/2$

$10 = 19.97t - 9.8t^2/2$

$4.9t^2 - 19.97t + 10 = 0$

$t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$t= \frac{19.9658877511823\pm \sqrt{(-19.9658877511823)^2 - 4*(4.9)*(10)}}{2*(4.9)}$

$t= \frac{19.9658877511823\pm14.24}{9.8}$

t = 3.49 or t = 0.58

We have 2 solutions for t, one is 0.58 when it first reach the blaze during the 1st shoot up, the other is 3.49s when it falls down

t is also the times it takes to travel across horizontally. We can use this to compute the horizontal distance between the fire-fighters and the building

$s_1 = v_ht_1 = 15*0.58 = 8.8 m$

$s_2 = v_ht_2 = 15*3.49 = 52.5m$

8 0

2 years ago

What is the gravitational force on a 35.0 kg object standing on the Earth's surface?

kari74 [83]

F=mg
F=35*9.81
F=343.35N

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3 years ago

On a trip you travel at a constant speed of 50 kilometers per hour North for 1 hour. Then you turn West and travel at a constant

polet [3.4K]

Answer:27 km per hour West + 17 km per hour North

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2 years ago

Using an inclined plane, what happens to the amount of work that has to be done?

weeeeeb [17]

A. The amount of work increases.
Imagine you are pushing a box on a flat surface. Now imagine pushing it up a steep hill. It gets harder and that's how I remember this.
Hope this helps.

8 0

3 years ago

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