Answer:
11.35 m/s
Explanation:
Given,
Weight of the bucket = 15 lb
radius of curvature, r = 4 ft
Minimum speed of the bucket = ?
Using equation of centripetal acceleration





Speed of the bucket = 11.35 m/s
Answer:
4.4 km
Explanation:
t = Time taken
u = Initial velocity = 24 m/s (Assumed)
v = Final velocity
s = Displacement
a = Acceleration = -0.065 m/s² (Assumed)
Distance = Speed × Time

The train travels for 9600 m.


The Distance the train traveled when it slowed down is 4.4 km
Explanation:
thet amplify DC, because of the voltage ( small current input signal)
Answer:
v = 4.264 m/s
Explanation:
It is given that,
Mass of the ball, m = 0.15 kg
Spring constant of the spring, k = 150 N/m
The spring is compressed by a distance, x = 0.05 m
The pellet's initial velocity is at an angle θ (θ < 90) above the horizontal.
Let v is the final speed of the projectile when it is at a distance h = 0.800 m below its initial height. It can be calculated using the conservation of energy as :



v = 4.264 m/s
So, the final speed of the projectile is 4.264 m/s. Hence, this is the required solution.
Light is refracted when it crosses the interface from air into glass in which it moves more slowly. Since the light speed changes at the interface, the wavelength of the light must change, also. The wavelength decreases as the light enters the medium and the light wave changes direction.