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marishachu [46]
3 years ago
10

if the equation y=3/2 x+5 were to be graphed in the xy-plane above, at what point would the graph intersect the line shown

Mathematics
1 answer:
adoni [48]3 years ago
3 0

Answer:

if you go on https://www.geogebra.org/ it will graph it for you

Step-by-step explanation:


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Answer:

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Step-by-step explanation:

1) In this question we've been given "a", the leading coefficient. and two roots:

x_{1}=\sqrt{5}\:x_{2}=2

2) There's a theorem, called the Irrational Theorem Root that states:

If one root is in this form x'=\sqrt{a}+b  then its conjugate x''=\sqrt{a}-b. is also a root of this polynomial.

Therefore

x_3=-\sqrt{5}

3) So, applying this Theorem we can rewrite the equation, by factoring. Remembering that x is the root. Since the question wants it in this expanded form then:

f(x)=3(x-\sqrt{5})(x+\sqrt{5})(x-2)\Rightarrow 3x^{3}-6x^{2}-15x+30

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