I hope this works
2(y-1)8=
16(y-1)
Based on the capacity of the container and the capacity currently being used, the amount of water in the container is <u>3/8 gallons. </u>
The container is capable of holding 1/2 gallons of water.
If it is holding 3/4 of that 1/2 gallons, the amount of water it would be holding is:
<em>= Capacity of container x Percentage full </em>
= 1/2 x 3/4
= 3/8 gallons of water
In conclusion, the container is currently holding 3/8 gallons of water.
<em>Find out more about this at brainly.com/question/11459708. </em>
Answer:

Step-by-step explanation:
<u>Properties of Logarithms</u>
We'll recall below the basic properties of logarithms:

Logarithm of the base:

Product rule:

Division rule:

Power rule:

Change of base:

Simplifying logarithms often requires the application of one or more of the above properties.
Simplify

Factoring
.

Applying the power rule:

Since


Applying the power rule:

Applying the logarithm of the base:

22 I think If I worked it out right
She has $12,488 in savings
Step-by-step explanation:
Ariana plans to use $260 less than three-fourths of savings to buy a car.
If the purchase price of the car is 9,340, we need to find how much
she has in savings
To find the savings
- Assume that she has $x in savings
- Write an equation of x
- Solve the equation to find x
∵ She has $x in savings
∵ She plans to use $260 less than three-fourths of savings
- Three-fourths means
and less than means subtract
∴ She plans to use
x - 26
∵ The purchase price of the car is 9,340
- Equate the expression of x by 9,340
∴
x - 26 = 9,340
Now let us solve the equation
∵
x - 26 = 9,340
- Add 26 to both sides
∴
x = 9,366
- Divide both sides by
∴ x = $12,488
She has $12,488 in savings
Learn more:
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