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san4es73 [151]
3 years ago
6

When the air resistance can be ignored the velocity of an object dropped initially from rest is given by the following equation

where g is free-fall acceleration
A. g*t^2/2
B. g*t
C. g*t/2
D. g
Physics
2 answers:
ad-work [718]3 years ago
8 0

Answer:

I am confused of your question. Do you want final velocity? To get final velocity, use (initial V)+(Gravity*Time)

Explanation:

Leviafan [203]3 years ago
3 0

Answer:

B. g*t

Explanation:

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The momentum of the second ball was 15 kg.m/s.

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In which collision some amount of kinetic energy of the system is lost that called inelastic collision. In purely inelastic collision, two bodies stick together. But principle of conservation of linear momentum is obeyed.

In the given question,

Two balls collide and after collision, the final momentum of the system = 18 kg.m/s.

Initial velocity of 1st ball of mass 3 kg is 1 m/s.

So, Initial momentum of first ball = mass × velocity = (3 kg) × (1 m/s) = 3 kg.m/s.

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