To solve this problem we will apply the concepts related to wave velocity as a function of the tension and linear mass density. This is
Here
v = Wave speed
T = Tension
= Linear mass density
From this proportion we can realize that the speed of the wave is directly proportional to the square of the tension
Therefore, if there is an increase in tension of 4, the velocity will increase the square root of that proportion
The factor that the wave speed change is 2.
Answer:Velocity = 6.325m/s
Directional angle= 18.43°
Explanation:
Using Right angle triangle
Let Velocity of ballon&hawk be VHB represent the height of the triangle.
Let Velocity of balloon angle ground be VBG represent adjacent of the triangle.
Let Velocity of hawk and ground BE VHG represent the hypothesis.
Theta = opp/Adj= VHB/VBG
using pythagorean
VHG= SQRT(VHB^2+VBG^2)
VHG= sqrt(2^2+6^2)
VHG= sqrt(4+36)
VHG= 6.325m/s
Tan theta= 2/6
Tan theta =0.3333
Tan^-1 0.3333=18.43°
Answer:
The acceleration of the object is
Explanation:
Given:
Initial velocity of object = 200 feet/second
Final velocity of object = 50 feet/second
Time of travel = 5 seconds
To calculate acceleration of the object we will find the rate of change of velocity with respect to time.
So, acceleration is given by:
where represents final velocity, represents initial velocity and is time of travel.
Plugging in values to evaluate acceleration.
The acceleration of the object is (Answer). The negative sign shows the object is slowing down.
Explanation:
Echoes occur due to the reflection of sound from any obstacle, but not all the reflected sound waves lead to the phenomenon of echo. For the echo to be heard it actually depends upon the human perception as well, human ears can encounter the difference between the sound wave directly form the source and the reflected sound waves only if there is a minimum time gap of one-tenth of a second. For this time gap in the atmosphere at normal temperature and pressure the obstacle must be at least 7 meters away from the sound source.
<h3><u>Answer;</u></h3>
= 8.55 Joules
<h3><u>Explanation;</u></h3>
Work done is the product of force and the distance moved by an object.
Work done = Force × distance
Force = 95 Newtons
Distance = X2 -X1
= 4 - (-5)
= 9 cm
Thus;
work done = 95 × 9/100
<u>= 8.55 Joules </u>