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galina1969 [7]
3 years ago
8

Write submultipels units of time​

Physics
1 answer:
Firdavs [7]3 years ago
8 0

What

is the the improvetanse of water in our body and how do

Or

open Meet and enter this code

Answer:

Or open Meet and enter this code to the source of definition and how to use it to make

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Select the correct answer.
elixir [45]

A) Energy is absorbed in the reaction.

Such reactions are called endothermic reactions.

5 0
3 years ago
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#86 can an object be moving when its acceleration is zero? can an object be accelerating when its speed is zero?
liraira [26]
Yes, an object<span> that was set in motion in the past by some force, but that is no longer being acted on by a net force, is </span>moving<span> but with </span>zero acceleration<span>, i.e. it is </span>moving<span> at constant velocity.</span>
7 0
3 years ago
A parked car's horn (belonging to a musician) emits a concert A of frequency 440 on a day when the speed of sound is 342 m/s. Yo
julsineya [31]

Answer:

19.08 m/s

Explanation:

f = actual frequency emitted by the parked car's horn = 440 Hz

V = speed of sound = 342 m/s

f' = frequency of the horn observed by you = 466 Hz

v = speed of your car moving towards the parked car = ?

frequency of the horn observed by you is given as

f' = \frac{Vf}{V - v}

466 = \frac{(342)(440)}{342 - v}

v = 19.08 m/s

3 0
3 years ago
An electron accelerated from rest through a voltage of 780 v enters a region of constant magnetic field. part a part complete if
maxonik [38]
The electron is accelerated through a potential difference of \Delta V=780 V, so the kinetic energy gained by the electron is equal to its variation of electrical potential energy:
\frac{1}{2}mv^2 =  e \Delta V
where
m is the electron mass
v is the final speed of the electron
e is the electron charge
\Delta V is the potential difference

Re-arranging this equation, we can find the speed of the electron before entering the magnetic field:
v= \sqrt{ \frac{2 e \Delta V}{m} } = \sqrt{ \frac{2(1.6 \cdot 10^{-19}C)(780 V)}{9.1 \cdot 10^{-31} kg} }=1.66 \cdot 10^7 m/s


Now the electron enters the magnetic field. The Lorentz force provides the centripetal force that keeps the electron in circular orbit:
evB=m \frac{v^2}{r}
where B is the intensity of the magnetic field and r is the orbital radius. Since the radius is r=25 cm=0.25 m, we can re-arrange this equation to find B:
B= \frac{mv}{er}= \frac{(9.1 \cdot 10^{-31}kg)(1.66 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19}C)(0.25 m)} =3.8 \cdot 10^{-4} T
3 0
3 years ago
PLEASE HELP show the calculation of the number of neutrons of hydrogen​
xz_007 [3.2K]
The answer is 2.3 hope this helps texted me and tell me if it’s right
7 0
3 years ago
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