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Sophie [7]
3 years ago
12

Equation of uniformly accelerated motion​

Physics
1 answer:
Kruka [31]3 years ago
6 0

Answer:

x₂ = x₁ + v₁t + at²/2

Explanation:

Right out of the textbook.

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3 years ago
A tennis ball is dropped from 1.62 m above the
natita [175]

Answer:

-5.63 m/s

Explanation:

Given:

y₀ = 1.62 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.62 m)

v = -5.63 m/s

8 0
2 years ago
A stone is dropped down a well and hits the water 2.50 s later. What is the depth from the edge of the well to the water? 61.3,
Gennadij [26K]

Answer;

30.6 m

Explanation;

All objects accelerate at the constant rate in the Earth's gravitational field. The gravitational acceleration, g = 9.8 m/s².

Distance traveled by an object falling down under a constant acceleration will be given the formula;

s = ut² + 1/2(gt²); but u the initial velocity is o

thus;

S =1/2(gt²)

  = 0.5 × 9.81 × 2.5 ²

  = 30.65

  ≈ 30.6 m

5 0
2 years ago
In this lab, you will observe current induced through the interaction of a magnet and wire coil, while changing one property of
Brrunno [24]

Answer:

How does magnet polarity affect the current flowing in a loop of wire?

Explanation:

5 0
3 years ago
Read 2 more answers
The brightest, hottest, and most massive stars are the brilliant blue stars designated as spectral class O. If a class O star wi
aksik [14]

Answer:

2.77 * 10^5 m/s

Explanation:

Let us recall that kinetic energy is given by 1/2 mv^2

Where;

m = mass of the body

v = velocity of the body

In this case,

m = 3.38 * 10^31 kg

KE= 1.30 * 10^42 J

KE = 1/2 mv^2

v = √2KE/m

v = √2 * 1.30 * 10^42/3.38 * 10^31

v = √7.69 * 10^10

v = 2.77 * 10^5 m/s

4 0
3 years ago
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