Answer:
Step-by-step explanation:
We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.
To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.
, where r represents radius of the circle.
Therefore, the exact area of the side walk is 
To find the approximate area of side walk let us substitute pi equals 3.14.
Therefore, the approximate area of the side walk is 
.
Easy one....
58
There is no difficult explanation. It’s always the left end of the box and whisker plot.
The original function f(x) = 2x+3.
And the transformed function is g(x) = 2x+4.
We can see that if we add 1 into function f(x), we get
f(x) +1 or 2x+3+1 = 2x+4.
<h2>
So, 1 is being added in original function f(x) and we get g function g(x) = 2x+4.</h2>
<em>According to rules of transformations, when we add some number k in the given function, it move k units up and if we subtract k from given function, it move k units down.</em>
<h3>Therefore, correct option is B option.</h3><h3>B. translation 1 unit up.</h3>
Answer:
The required equation will be:
Step-by-step explanation:
We know the slope-intercept form of the line equation
where 'm' is the slope or rate of change and 'b' is the y-intercept of the equation
- Let 'n' represents the number of students (n).
- Let 'c' represents the cost budget.
Given that Bea's catering charges $3 per person.
- Thus, the slope or rate of change = m = 3 dollars per person
Given that the clean-up fee to cater banquets = $60
In other words, $60 is the initial condition or y-intercept.
- Thus, the y-intercept b = 60
Given that the cost budget = c = $200
Thus, the equation becomes
c = mn+b
substituting c = 200, m = rate of cgange = 3, b = 60
200 = 3n + 60 ∵ comparing with y = mx+b
Thus, the required equation will be:
Step-by-step explanation:
In this problem, we need to arrange 150 chairs in rows for a school play. You want each row to have the same number of chairs.
We can find the prime factorization of 150 as follows :
150 = 2, 3, 5, 5
150 is not a perfect square. 144 is a perfect square and 12² = 144. So, there are 12 possible arrangements.
