P(<100) = P((new or change) & <100) = P(new & <100) + P(change & <100)
... = P(<100 | new)*P(new) + P(<100 | change)*P(change)
... = 0.90*0.70 + 0.20*0.30
... = 0.63 + 0.06 = 0.69 . . . . probability of completing a transaction in < 100 ms
Answer:
100° it has to be a
length of 20 or like my 100 worlds longest
Here hope this help the solution is X= -2 and y=9
Answer: 2 2/3 is located on the third line after two and 1 5/6 is located on the last line after one
Step-by-step explanation:
