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Sphinxa [80]
3 years ago
7

A plumbers bill is £463.20 plus VAT. The current rate of VAT is 20% what is the actual cost of work done

Mathematics
1 answer:
Jet001 [13]3 years ago
4 0
Actual cost = bill + VAT*bill
  = bill*(1 +VAT)
  = £463.20*(1 +0.20)
actual cost = £555.84
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How do I solve the absolute value of -5x=45
GREYUIT [131]
Well, You divide both sides by -5.

<span><span><span>−<span>5x/</span></span><span>−5</span></span>=<span>45/<span>−5

</span></span></span><span>x=<span>−9

</span></span>Answer:

<span>x=<span>−<span>9</span></span></span>
7 0
3 years ago
What is 5 1/4 as a single fraction greater than 1
Sauron [17]

Answer:

21/4

Step-by-step explanation:

(5 * 4) + 1

20 + 1

21/4

7 0
3 years ago
Twice the difference of a number and 1 is 4 more than that number. Find the numbers using Polyas 4 step
const2013 [10]

Answer:

6

Step-by-step explanation:

2 times the difference of a number and 1 = 4 plus that number

In other to express the word problem Mathematically ; let the number = x

2(x - 1) = 4 + x

Expand

2x - 2 = 4 + x

Collect like terms

2x - x = 4 + 2

x = 6

Hence, the number is 6

4 0
3 years ago
Which of the following equations could be th equation to represent the given graph? Make sure you explain your answer thoroughly
Alex17521 [72]

Answer:

Option (C) is correct.

Step-by-step explanation:

The given options of the possible equation for the graph are as follows:

(A) y=2\left(\frac{3}{2}\right)^x \\\\(B) y=-2\left(\frac{3}{2}\right)^{-x} \\\\(C) y=2\left(\frac{2}{3}\right)^x \\\\(D) y=-2\left(\frac{2}{3}\right)^{-x} \\\\

The given graph is decreasing and at x=0, y=2.

So, first checking the value of the given options for x=0

(A) y=2\left(\frac{3}{2}\right)^0=2\times 1= 2 \\\\(B) y=--2\left(\frac{3}{2}\right)^{-0}= -2\times 1= -2 \; (not\; possible) \\\\(C) y=2\left(\frac{2}{3}\right)^0= 2\times 1= 2 \\\\(D) y=2\left(\frac{2}{3}\right)^{-0} = -2\times 1= -2 \; (not\; possible)

As, for x=0, y=2, so options (C) and (D) are not possible, so rejected.

Now, checking the nature (increasing or decreasing) of the given equation by differentiating it.

For option (A),

\frac{dy}{dx}=2\left(\frac{3}{2}\right)^{x}\times \ln\left(\frac{3}{2}\right)

As \ln \left(\frac{3}{2}\right)=\ln(1.5)>0 \;and\; \left(\frac{3}{2}\right)^{x} >0

So, \frac{dy}{dx}>0

Therefore, the function in option (A) is increasing function.

Similarly, for option (C),

\frac{dy}{dx}=2\left(\frac{2}{3}\right)^{x}\times \ln\left(\frac{2}{3}\right)

As \ln \left(\frac{2}{3}\right)=\ln(0.67)0

So, \frac{dy}{dx}

Therefore, the function in option (C) is decreasing function.

As the given graph is decreasing, so, (C)  representsy=2\left(\frac{2}{3}\right)^x the given graph.

Hence, option (C) is correct.

6 0
3 years ago
Help me please Asap
Eduardwww [97]

Answer:

it is the last one {-4, -1, 0, 1, 2}

Step-by-step explanation:

6 0
2 years ago
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