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3 years ago

⦁ Which species do you think is best adapted to a diet of small, delicate seeds? Explain why you think so.

Physics

1 answer:

Angelina_Jolie [31]3 years ago

7 0

Answer:

Finches

Explanation:

Because they are relatively small birds and eat a diet of seeds

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If an object is dropped from a tall building and hits the ground 3.0 s. later, what is the magnitude of the object's displacemen

marin [14]

Find the velocity of the object after one second.

v = vo + at

v = (0 m/s) + (9.8 m/s^2)(1 s)

v = 9.8 m/s

Now, using that, you can find the displacement in that one second between 1 and 2.

d = vot + (1/2)at^2

d = (9.8 m/s)(1 s) + (1/2)(9.8 m/s^2)(1 s)^2

d = 14.7 m

5 0

3 years ago

Read 2 more answers

In a closed system, _____ energy is equal to potential energy plus kinetic energy.

Kobotan [32]

The answer is mechanical

4 0

4 years ago

Read 2 more answers

A cyclist moving with a constant velocity of 6.0 m/s forward passes a car that is just starting. If the car has a constant accel

sergiy2304 [10]

After 6 seconds, the car will surpass the cyclist.

<h3><u>Explanation:</u></h3>

The speed of the cyclist = 6 m/s.

Let after time t sec, the car will overtake the cyclist.

So, distance covered by the cyclist in t sec = 6t m

Initial velocity of the car is 0 m/s, because the car is just starting.

Acceleration of the car = $2 m/s^2$ .

Final velocity of the car =6 m/s.

So to cover the distance 6t, the time required by the car = $\frac{1}{2} \times a \times t^2 = \frac{1}{2} \times 2 \times t^2$

$6t = \frac{1}{2} \times 2 \times t^2\\6t = t^2$

t =6 sec

So, after 6 seconds, the car will surpass the cycle.

6 0

3 years ago

A 59.7 g piece of metal that had been submerged in boiling water was quickly transferred into 60.0 mL of water initially at 22.0

Anna007 [38]

Answer:

$s = 382.45 J/kg C$

Explanation:

Here by energy equivalence we can say that energy given by the metal piece is same as the energy absorbed by the water

so here we have

$m_1s_2\Delta T_1 = m_2s_2 \Delta T_2$

here we know that

$m_1 = 60 mL = 0.060 kg$

$s_1 = 4186 J/kg C$

$\Delta T_1 = 28.5 - 22$

$m_2 = 59.7 g = 0.0597 kg$

$\Delta T_2 = 100 - 28.5$

$0.060(4186)(28.5 - 22) = (0.0597)(s)(100 - 28.5)$

$1632.54 = 4.27 s$

$s = 382.45 J/kg C$

5 0

4 years ago

A bike is pushed with a net force of 2.5 N, and it accelerates 0.5 m/s2. If you pushed the bike with twice that amount of net fo

lord [1]

1.0m/s2 because net force and acceleration have a proprtional relationship

8 0

4 years ago