On a day when the speed of sound is 340 m/s, a ship sounds its whistle. The echo of the sound from the shore is heard at the shi
1 answer:
The distance of the ship from the shore is 1020m
<u>Explanation:</u>
Given:
Speed, s = 340 m/s
Time, t = 10s
Distance, x = ?
The sound is going to have to go to shore, then come back.
The total round-trip distance is
D = speed X time
D = (340 m/s) * (6.0 s)
D = 2,040 m
But as previously stated, the sound had to get there, then come back. So the actual ship-to-shore distance is only half that.
x = D/2
Therefore, the distance of the ship from the shore is 1020m
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Answer:
34.70 N
Explanation:
Given :
F~ 1 = 43 N in direction 38◦
F~ 2 = 26 N in direction −140◦
F~ 3 = 27 N in direction 110◦
Therefore,
F~x = 43 cos (38) + 26 cos (-140) + 27 cos (110)
= 43 (0.7) + 26 (-0.7) + 27 (-0.3)
= 3.8
F~y = 43 sin (38) + 26 sin (-140) + 27 sin (110)
= 43 (0.6) + 26 (-0.6) + 27 (0.9)
= 34.5
so, F~ =
= 34.70 N
Answer:
Explanation:
We are given that
Frequency,f=800KHz=
Distance,d=4.5 km=
1 km=1000 m
Electric field,E=0.63V/m
We have to find the magnetic field amplitude of the signal at that point.
We know that