Answer:
No, function is not one-to-one
No, function is not onto
Step-by-step explanation:
We are given that a function
f:![Z\rightarrow Z](https://tex.z-dn.net/?f=Z%5Crightarrow%20Z)
![f(x)=\mid{x-5}\mid +5](https://tex.z-dn.net/?f=f%28x%29%3D%5Cmid%7Bx-5%7D%5Cmid%20%2B5)
If function is one-to-one then different x have different image .
Domain =Z
Codomain=Z
When function is onto then range=Codomain
Substitute x=1
Then ,![f(1)=\mid{1-5}\mid+5=4+5=9](https://tex.z-dn.net/?f=f%281%29%3D%5Cmid%7B1-5%7D%5Cmid%2B5%3D4%2B5%3D9)
When substitute x=9
Then , we get ![f(9)=\mid {9-5}\mid +5=4+5=9](https://tex.z-dn.net/?f=f%289%29%3D%5Cmid%20%7B9-5%7D%5Cmid%20%2B5%3D4%2B5%3D9)
Image of 1 and 9 are same hence, function is not one-to-one.
Negative elements of Z and Zero has no preimage.Therefore, function is not onto.
256 * 40 = 10,240 cm needed
so if the balls are 30 cm each then
10, 240 divided by 30 = 341.3
so the teacher will need 342 balls.
X = 7 and x = 1
Two solutions were found.
The answer is
-11.1 i am sure :)
Answer: The perpendicular slope is ![-3](https://tex.z-dn.net/?f=-3)
Step-by-step explanation:
Find the perpendicular slope (the negative reciprocal of
):
![-3](https://tex.z-dn.net/?f=-3)