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SOVA2 [1]
3 years ago
7

5/6 2/6 6/6 least ti greatest?

Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0
Convert all the fractions into decimals so we can see better which is greater and which a smaller.

Simply divide the top by its bottom to get the decimal.

5/6 = 0.8333...
2/6 = 0.3333...
6/6 = 1

We can clearly see the least to greatest numbers.

0.3333..., 0.8333..., 1
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Researchers are investigating the effectiveness of leg-strength training on cycling performance. A sample of 7 men will be selec
ruslelena [56]

Answer:

A. The interval will be narrower if 15 men are used in the sample.

Step-by-step explanation:

Hello!

When all other things remain the same, which of the following statements about the width of the interval is correct?

A. The interval will be narrower if 15 men are used in the sample.

B. The interval will be wider if 15 men are used in the sample.

C. The interval will be narrower if 5 men are used in the sample.

D. The interval will be narrower if the level is increased to 99% confidence.

E. The interval will be wider if the level is decreased to 90% confidence.

Consider that the variable of interest "Xd: Difference between the peak power of a cyclist before training and after training" has a normal distribution. To construct the confidence interval for the population mean of the difference you have to use a pooled t-test.

The general structure for the CI is "point estimate"±" margin fo error"

Any modification to the sample size, sample variance and/or the confidence level affect the length of the interval (amplitude) and the margin of error (semiamplitude)

The margin of error of the interval is:

d= t_{n-1;1-\alpha /2} * (Sd/n)

1) The sample size changes, all other terms of the interval stay the same.

As you can see the margin of error and the sample size (n) have an indirect relationship. This means, that when the sample size increases, the semiamplitude decreases, and when the sample size decreases, the semiamplitude increases.

↓d= t_{n-1;1-\alpha /2} * (Sd/↑n)

↑d= t_{n-1;1-\alpha /2} * (Sd/↓n)

Correct option: A. The interval will be narrower if 15 men are used in the sample.

2) The confidence level has a direct relationship with the semiamplitude of the interval, this means that when the confidence level increases, so do the semiamplitude, and if the level decreases, so do the semiamplitude:

↓d= ↓t_{n-1;1-\alpha /2} * (Sd/n)

↑d= ↑t_{n-1;1-\alpha /2} * (Sd/n)

I hope it helps!

4 0
4 years ago
Helllllllllllpppppppppppppppppp
leva [86]

Answer: Negative 1 and one-fifth

Step-by-step explanation:

Add the two numbers lol

Hope this help

I'm a also a K12 kid too btw.

3 0
3 years ago
Sdfghjkljhgfdxzs idk
levacccp [35]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please help and show work
Eva8 [605]

Answer:

1) x(x+7)

3) (x+5)*(x+4)

4) (x-6)*(x-8)

5) x(2x+21)+11

6) 5(a-5)*(a+5)

7) (4x+3)*(2x-3)

8) 4( x²-6xy+8)

Step-by-step explanation:

4 0
3 years ago
X/2 = 4/16<br><br> solve for x<br><br>Also: if possible/ any please show work!
lana66690 [7]
<span>X/2 = 4/16

This is where you would use cross-multiplication.
Multiply the x with 16 and the 2 with 4.

16x = 8

Now divide everything by 16.
x = 0.5</span>
6 0
3 years ago
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