A^2+B^2=C^2
6*6+6*6 = sqrt(72) so... 8.49 blocks in a Northwest Direction
Answer:
At 95% confidence level, the confidence interval that is likely to contain the percent, , of all teenagers at the wheel when an accident occurred is given as follows;
12.7% < < 18.6%
Step-by-step explanation:
The parameters given are as follows;
Sample size, n = 582
Proportion of accidents where teenagers are at the wheel, = 15.6%
x = 0.156*582 ≈ 91
The formula for the confidence interval is as follows;
Where:
z = z value at the confidence level
We therefore have;
At a confidence level of 95%, z = 1.96
The confidence interval at 95% confidence level is therefore;
12.7% < < 18.6%.
Answer:
Step-by-step explanation:
x=√(5+2√6)/(5-2√6)
x²(x-10)²=1
substitute the value of x in the equation
[√(5+2√6)/(5-2√6)]²(√(5+2√6)/(5-2√6) -10)²=
solve :
(49+20√6)(49-20√6)=1 multiply
1=1 proved
Answer:
3 < x < 8
Step-by-step explanation: