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laiz [17]
3 years ago
10

Is interquadral range a measure of central tendency

Mathematics
1 answer:
Alex777 [14]3 years ago
6 0
Yes it is.............,.
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Brainliest is given to the correct answer!
OlgaM077 [116]

Answer:

a. p = 2\pi r + 8r

b. r = \frac{p}{2\pi + 8}

Step-by-step explanation:

a. Radius of semicircle (r) = r

Diameter of semicircle (d) = 2r

Length of rectangle (l) = 2*diameter of semicircle = 2*2r = 4r

Distance around the track (p) = circumference of circle + 2(l)

Note: the two semicircles of the track = 1 full circle

Circumference of full circle = πd = π*2r = 2πr

Distance around the track:

p = 2πr + 2(4r)

p = 2πr + 8r

b. Rewriting the formula to make radius, r, the subject of the formula in terms of distance around the track.

p = 2\pi r + 8r

Factor out r

p = r(2\pi + 8)

Divide both sides by (2π + 8)

\frac{p}{2\pi + 8} = \frac{r(2\pi + 8)}{2\pi + 8}

\frac{p}{2\pi + 8} = r

r = \frac{p}{2\pi + 8}

6 0
4 years ago
Right answers only!!!
Nata [24]

Step-by-step explanation:

7

8 0
3 years ago
Read 2 more answers
Name the Property Shown: 16=16 Question 1 options: Symmetric Property Transitive Property Reflexive Property Distributive Proper
Lemur [1.5K]

Answer:

reflexive property

Step-by-step explanation:

reflexive property states that a number equals itself, a = a, so since 16 = 16, or 16 equals itself, it's reflexive.

3 0
3 years ago
Lauren is the touring students at the library on Saturday if she is a library for a total of 6 hours and she helps each student
wariber [46]
Lauren ‘tutored’(i think that’s what the question said idk) 4 students. take the 3/4 and multiply it by the value of time(6 hours). the calculated answer is 4.5, but you can’t half-tutor a student, and you can’t round up, so the answer is 4
8 0
4 years ago
PLEASE HELP SOLVE FOR Y
alexgriva [62]

Hello!

\large\boxed{y = 5(\frac{1}{2})^{x} }

Recall that the equation of an exponential graph is:

y = a(b)^{x}

We can see from the graph there is a y-intercept at y = 5. Plugging in 0 for x results in:

5 = a(b)^{0}\\\\5 = a(1)\\\\a = 5

Solve for b by plugging in another point on the graph:

10 = 5(b)^{-1}\\\\2 = b^{-1}\\\\b = 1/2

Write the final equation:

y = 5(\frac{1}{2})^{x}

6 0
3 years ago
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