one of the sides of a square has vertices at (8,-2) and (8,4). What is the length of the side of the square

1 answer:

3 0

$length = \sqrt{{(x1 - x2)}^{2} + {(y1 - y2)}^{2} } \\ = \sqrt{ {(8 - 8)}^{2} + {( - 2 - 4)}^{2} } \\ = \sqrt{ {( - 6)}^{2} } \\ = \sqrt{36} \\ = 6 \\ therefore \: length \: of \: a \: side \: of \: the \: square \: is \: 6 \: units$

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Help please will mark best answer

77julia77 [94]

I figured out the first question, the second one in lost on.

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$\frac{(6-x)}{(x+7)(x-4)}* \frac{(x+6)(x-6)}{(x+9)(x-4)}$

Cancel the like factors *excuse the zero im just showing you*

$\frac{(0)}{(x+7)} *\frac{(x+6)}{(x-9)}$

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