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Drupady [299]
3 years ago
10

Complete the sentence. Friction always ____________

Physics
2 answers:
luda_lava [24]3 years ago
7 0

Answer:

B- Opposes the motion

Explanation:

When two object touches each other. friction acts in a opposite direction to the motion of the object

kobusy [5.1K]3 years ago
7 0
B. Opposes the motion.

A marble rolling across a flat surface will not roll forever. This is due to friction. The marble rubs against the flat surface, slowing down until it finally stops.
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(a) State and explain which of the arrangements would have the greater extension of spring(s). (b) Explain if there are any chan
swat32

Answer:
arrangement 2

Explanation:
arrangement 1's spring would broke idek

3 0
2 years ago
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If you apply a force of 100 N to the level, how much force is applied to lift the crate?
Kaylis [27]
I believe that the answer is B. 133 N
4 0
3 years ago
Average speed can be represented by the mathematical expression
nevsk [136]

Average speed is defined as total distance moved in total interval of time

so it is given as

v_{avg} = \frac{distance}{time}

now here is we show distance by "d" and time by"t"

then we will have mathematical expression as follows

v = \frac{d}{t}

5 0
3 years ago
you have been called to testify as a as an expert witness in a trial involving a head-on collision Car A weighs 1515 pounds and
GrogVix [38]

Answer:

70.6 mph

Explanation:

Car A mass= 1515 lb

Car B mass=1125 lb  

Speed of car B is 46 miles/h

Distance before locking, d=19.5 ft

Coefficient of kinetic friction is 0.75

Initial momentum of car B=mv where m is mass and v is velocity in ft/s  

46 mph*1.46667=67.4666668 ft/s

Momentum_B=1125*67.4666668 ft/s

Initial momentum of car A is given by

Momentum_A=1515v_a where v_a is velocity of A

Taking East as positive and west as negative then the sum of initial momentum is

1515v_a-(1125*67.4666668 ft/s)

The common velocity is represented as v_c hence after collision, the final momentum is

Momentum_final=(m_a+m_b)v_c=(1515+1125)v_c=2640v_c

From the law of conservation of linear momentum, sum of initial and final momentum equals each other hence

1515v_a-(1125*67.4666668 ft/s)= 2640v_c

The acceleration of two cars a=-\mug=-0.75*32.17=-24.1275 ft/s^{2}

From kinematic equation

v^{2}=u^{2}+2as hence

v^{2}-u^{2}=2as

0^{2}-(v_c)^{2}=2*-24.1275*19.5

v_c=\sqrt{2*24.1275*19.5}=30.67 ft/s

Substituting the value of v_c in equation 1515v_a-(1125*67.4666668 ft/s)= 2640v_c

1515v_a-(1125*67.4666668 ft/s)= 2640*30.67

1515v_a=(1125*67.4666668 ft/s)+2640*30.67

v_a=\frac {156868.8}{1515}=103.5438 ft/s

\frac {103.5438}{1.46667}=70.59787 mph\approx 70.60 mph

3 0
3 years ago
Giving brainliest!! if you answer correctly :) (30pts)
AnnZ [28]

Answer:

32000joule.

Explanation:

given

mass. (m)=160kg

speed (v)=20m/s

now

kinetic energy =1/2 (mv²)=1/2 ×{160×20²}=32000joule.

8 0
3 years ago
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