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sp2606 [1]
3 years ago
6

What factors affect the gravitational pull of two massive objects?​

Physics
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:Mass and distance

Explanation:The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases.

Hope this helps!!

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Water near the poles would most likely be stored as
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3 years ago
A motorcycle is travelling at a constant velocity of 30ms. The motor is in high gear and emits a hum of 700Hz. The speed of soun
timurjin [86]

Answer:

a) T=1.43\times 10^{-3}\ s

b) d=0.0429\ m

c) \lambda=0.4857\ m

d) f_o=767.7\ Hz

Explanation:

Given:

  • velocity of the sound from the source, S=340\ m.s^{-1}
  • original frequency of sound from the source, f_s=700\ Hz
  • speed of the source, v_s=30\ m.s^{-1}

(a)

We know time period is inverse of frequency:

Mathematically:

T=\frac{1}{f}

T=\frac{1}{700}

T=1.43\times 10^{-3}\ s

(b)

Distance travelled by the motorcycle during one period of sound oscillation:

d=v_s.T

d=30\times 1.43\times 10^{-3}

d=0.0429\ m

(c)

The distance travelled by the sound during the period of one oscillation is its wavelength.

\lambda=\frac{S}{f}

\lambda=\frac{340}{700}

\lambda=0.4857\ m

(d)

observer frequency with respect to a stationary observer:

<u>According to the Doppler's effect:</u>

\frac{f_o}{f_s}= \frac{S+v_o}{S-v_s} ...........................(1)

where:

f_o\ \&\ v_o are the observed frequency and the velocity of observer respectively.

Here, observer is stationary.

\therefore v_o=0\ m.s^{-1}

Now, putting values in eq. (1)

\frac{f_o}{700}= \frac{340+0}{340-30}

f_o=767.7\ Hz

5 0
3 years ago
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