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The distance of the cell phone from the western tower is 27.47 miles and from the eastern tower is 1.76 miles
<u>Explanation:</u>
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The sketch is attached for the reference.
tan (10) =
tan (70) =
Therefore, the distance of the cell phone from the western tower is 27.47 miles and from the eastern tower is 1.76 miles
Answer:
6.46
Step-by-step explanation:
h(t) = (1/2) + v0t + h0
Origin is at surface of water (h = 0), up is positive.
a = -g = -9.8 m/
v0 = 25 m/s
h0 = 50 m
h(t) = -4.9t2 + 25t + 50
Find t when
7 = + 25t + 50
- 25t - 43 = 0
t = [1/(2*4.9)] [25 ±√( + 4*4.9*43)]
t = (0.102)(25 ± 38.312)
t > 0 ⇒ use only the positive square root
t = (0.102)(25 + 38.312) ≅ 6.46 s
It is 7m above the water at about 6.46 s