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2 years ago

Every student in your history

Mathematics

1 answer:

kvv77 [185]2 years ago

8 0

It would be a 1 in 4 chance

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A quadratic function has a vertex of (0,7) and passes through the point (2, 3). Which of

Arlecino [84]

Answer:

Y = -2X + 7

Step-by-step explanation:

Y = a(x-h)^2 + k

From (h,k) h = 0 k = 7 x = 2 y = 3

3 = a(2-0) + 7

3 = 2a - 0 + 7

Collect like terms

2a = 3 - 7

2a = -4

Divide both sides by 2

2a/2 = -4/2

a = -2

y = a(x-h) + k

y = -2(x-0) + 7

y = -2x + 0 + 7

y = -2x + 7 or

y + 2x - 7 = 0

8 0

2 years ago

Is this right. Please help me

My name is Ann [436]

Answer:

ye that is the correct answer

3 0

3 years ago

If the density of a 35.cm3 block of wood is .85 g./ml calculate the woods mass.

Reil [10]

So the equation you're going to be using is mass = density x volume
So the volume of your block is 35cm^3, and your density is .85g/ml

so your equation would be

mass=.85g/ml x 35cm^3

your final answer is 29.75g/cm^3

Hope this helps :)

6 0

3 years ago

Find an explicit formula for the geometric sequence -40,-20,-10......

garik1379 [7]

Answer:

The explicit formula for the geometric sequence is $c(n) = -40\cdot \left(\frac{1}{2} \right)^{n-1}$ .

Step-by-step explanation:

By definition of geometric sequence, we should use the following expression:

$c(n) = c_{1}\cdot r^{n-1}$ , $n \ge 1$ (1)

Where:

$c_{1}$ - First term.

$r$ - Geometric rate.

$n$ - Position of the element within the series.

If we know that $c_{1} = -40$ and $r = \frac{1}{2}$ , then the explicit formula for the geometric sequence is:

$c(n) = -40\cdot \left(\frac{1}{2} \right)^{n-1}$

The explicit formula for the geometric sequence is $c(n) = -40\cdot \left(\frac{1}{2} \right)^{n-1}$ .

3 0

3 years ago

The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source

Bezzdna [24]

Answer:

<em>The voltage at the middle source is</em> $(2-4\mathbf{i})\ V$

Step-by-step explanation:

<u>Voltage Sources in Series</u>

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

$2 + 6\mathbf{i}$

$a + b\mathbf{i}$

$2 - 5\mathbf{i}$

The sum of these voltages is:

$V_t=4+a+(6+b-5)\mathbf{i}$

Operating:

$V_t=4+a+(1+b)\mathbf{i}$

We know the total voltage is $6-3\mathbf{i}$ , thus:

$4+a+(1+b)\mathbf{i}=6-3\mathbf{i}$

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is $(2-4\mathbf{i})\ V$

5 0

2 years ago