$(f-g)(x)=f(x)-g(x)\\\\\text{We have}\ f(x)=-2x^2-2x-3\ \text{and}\ g(x)=3x^2-4x-4.\\\\\text{Substitute:}\\\\(f-g)(x)=(-2x^2-2x-3)-(3x^2-4x-4)\\\\(f-g)(x)=-2x^2-2x-3-3x^2+4x+4\qquad\text{combine like terms}\\\\(f-g)(x)=(-2x^2-3x^2)+(-2x+4x)+(-3+4)\\\\(f-g)(x)=-5x^2+2x+1$

3 0

3 years ago

If the area of the rectangle is five times the area of the triangle work out the width of the rectangle please help !

Mariulka [41]

Answer:

Insufficient Data

Step-by-step explanation:

Please correct the problem. Given details are not enough or/and precise to suggest solution

6 0

3 years ago

ron wants to build a ramp with a length of 14 ft and an angle of elevation of 26° the height of the ramp is about 6.1 ft. what i

Bezzdna [24]

Answer:

12.58 feet.

Step-by-step explanation:

Ron wants to build a 14 ft. ramp with an angle of the rise of 26° and the height of the ramp is about 6.1 ft.

We have to find out the length of the base of the ramp.

Now, the ramp forms a right triangle with the base and the height and here, the hypotenuse of the triangle is the ramp itself i.e. 14 ft.

If the base length is x feet, then we can write using the trigonometry

$\cos 26^{\circ} = \frac{\textrm{Base}}{\textrm {Hypotenuse}} = \frac{x}{14}$

⇒ x = 14 cos 26° = 12.58 feet. (Answer)

4 0

3 years ago