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LenKa [72]
3 years ago
14

How do I get an equation from 9x-y=45 but the equation has to equal y

Mathematics
2 answers:
joja [24]3 years ago
8 0
<span>Add {Y} to both sides to get 9x=45+y
Subtract 45 from both sides and you will get Y=9x-45</span>
Brilliant_brown [7]3 years ago
6 0
First add y to both sides to get 9x=45+y than subtract 45 from both sides to get 9x-45=y or y=9x-45
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Which values for x make this inequality true?<br><br> −15x+4≤39
nadezda [96]

Answer:

x ≥ -7/3

Step-by-step explanation:

<h3>General Formulas and Concepts:</h3>

Pre-Algebra

<h3>Order of Operations: BPEMDAS</h3>

Brackets

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define Inequality

-15x + 4 ≤ 39

Step 2: Solve for x

Subtract 4 on both sides:                     -15x ≤ 35

Divide -15 on both sides:                      x ≥ -7/3

Here we see that any value x greater than or equal to -7/3 would work as a solution to the inequality.

8 0
3 years ago
Please help me with this
TEA [102]

Answer:

6y

Step-by-step explanation:

The two figure are squares with the same area

side = √area = √y^2 = y (with y>0 because a length can‘t be negative)

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3 years ago
Please help me with both questions!!!!​​
Naya [18.7K]

Answer:

Step-by-step explanation:

16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a  dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

or x+2y=8

as the line is solid

so either≤ or ≥

consider x+2y≥8

put x=0,y=0

0≥8

which is impossible.

(0,0) does not satisfy the graph.

which is true as graph lies above the line.

again eq. of line through (2,3) and (4,4) is

y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0
3 years ago
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