If P <span>is the midpoint of DE then
DE = 2(DP)
10x - 12 = 2(3x + 2)
10x - 12 = 6x + 4
10x - 6x = 4 + 12
4x = 16
x = 16/4
x = 4
DP = 3x + 2 = 3 * 4 + 2 = 12 + 2 = 14 units</span>
Answer:
5/9, 2/7, 3/10 are all rational numbers
Step-by-step explanation:
Remember that all rational numbers are able to be written as a fraction or ratio of two integers.
Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
1. True
2. False
3. False
4. True
Answer:
4x +1
Step-by-step explanation:
f(x) = 3x - 1
g(x) = x + 2,
(f +g)(x)= 3x-1 + x+2
Combine like terms
=4x +1
